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Updated on: 27 Nov 2019, 21:35
Originally posted by CareerGeek on 27 Nov 2019, 18:10.
Last edited by CareerGeek on 27 Nov 2019, 21:35, edited 1 time in total.
Last edited by CareerGeek on 27 Nov 2019, 21:35, edited 1 time in total.
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David’s age is 1/6th of his father’s age. David’s father’s age will be twice of Alice’s age after 10 years. If Alice’s eighth birthday was celebrated two years before, then what is David’s present age ?
A. 30
B. 24
C. 18
D. 6
E. 5
Posted from my mobile device
A. 30
B. 24
C. 18
D. 6
E. 5
Posted from my mobile device
27 Nov 2019, 19:26
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Dillesh4096
David’s age is 1/6th of her father’s age. David’s father’s age will be twice of Alice’s age after 10 years. If Alice’s eighth birthday was celebrated two years before, then what is David’s present age ?
A. 30
B. 24
C. 18
D. 6
E. 5
Posted from my mobile device
A. 30
B. 24
C. 18
D. 6
E. 5
Posted from my mobile device
Please mention source when you post a question.
A’s 8th birthday was 2 yrs back, so she is 10 now.
After 10 yrs she will be 20 and D’s father will be twice or 40, so present age of father is 40-10=30
Now D is 1/6th of 30 or 5.
E
wordings are confusing. David is 1/6th of HER father. Who is her here? If David, then in all probability it should be his
27 Nov 2019, 21:48
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chetan2u
Dillesh4096
David’s age is 1/6th of her father’s age. David’s father’s age will be twice of Alice’s age after 10 years. If Alice’s eighth birthday was celebrated two years before, then what is David’s present age ?
A. 30
B. 24
C. 18
D. 6
E. 5
Posted from my mobile device
A. 30
B. 24
C. 18
D. 6
E. 5
Posted from my mobile device
Flawed question.
Please mention source when you post a question.
A’s 8th birthday was 2 yrs back, so she is 10 now.
After 10 yrs she will be 20 and D’s father will be twice or 40.
Now D is 1/6th but you can’t have 1/6 of 40.
Even wordings are confusing. David is 1/6th of HER father. Who is her here? If David, then in all probability it should be his
Let the present age of David = x.
Present age of Alice = 8 + 2 = 10
-- David ------ Father ------ Alice ---- Time
---- x ------------ 6x --------- 10 ----- Present
- x + 10 ----- 6x + 10 ------ 20 ----- 10 years later
Given, David’s father’s age will be twice of Alice’s age after 10 years
--> 6x + 10 = 2*20 = 40
--> 6x = 40 - 10 = 30
--> x = 30/6 = 5
After 10 yrs she will be 20 and D’s father will be twice or 40.
Now D is 1/6th but you can’t have 1/6 of 40.
Referring to your logic, Father is 40 years old 10 years later, NOT NOW.
So, present age of Father = 40 - 10 = 30
David's age is 1/6th of Father's age = 1/6*30 = 5
So, i don't see what's wrong in that!
Definitely agree with you about the word HER, same is edited to HIS
