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Shikhar22
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The credited answer is indeed correct.

5 identical pieces of wire attached end to end form one long wire whose length is 1 meter = 100 cm.

So, we have the following.

__________ __________ __________ __________ __________

At each joint, the wires overlap by 4 cm.

Since there are 4 joints, the overlaps use up 4 x 4 cm = 16 cm.

So, the total length of the short wires combined is 100 cm + 16 cm = 116 cm.

116/5 = 23.2.

The correct answer is (C).

Many people who miss this question choose (D), thinking that, since there are 5 short wires, there are 5 overlaps, and that therefore the total length of the short wires is (5 x 4 cm) + 100 cm = 120 cm. However, as we saw above, there are only four joints.

So, like many GMAT questions, this question goes beyond testing our math skills to testing whether we understand something nonobvious about the scenario.

Hey Marty. Thank you for the explanation. My only doubt is that when two wires overlap, doesn’t it make 4+4 cm of wire overlap because the two wires overlap to 4cm each. In that case the additional overlapping length should amount to 32 and not 16. I can’t stop scratching my head over this. Maybe I’ve got this wrong?

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MartyTargetTestPrep
The credited answer is indeed correct.

5 identical pieces of wire attached end to end form one long wire whose length is 1 meter = 100 cm.

So, we have the following.

__________ __________ __________ __________ __________

At each joint, the wires overlap by 4 cm.

Since there are 4 joints, the overlaps use up 4 x 4 cm = 16 cm.

So, the total length of the short wires combined is 100 cm + 16 cm = 116 cm.

116/5 = 23.2.

The correct answer is (C).

Many people who miss this question choose (D), thinking that, since there are 5 short wires, there are 5 overlaps, and that therefore the total length of the short wires is (5 x 4 cm) + 100 cm = 120 cm. However, as we saw above, there are only four joints.

So, like many GMAT questions, this question goes beyond testing our math skills to testing whether we understand something nonobvious about the scenario.

Hey Marty. Thank you for the explanation. My only doubt is that when two wires overlap, doesn’t it make 4+4 cm of wire overlap because the two wires overlap to 4cm each. In that case the additional overlapping length should amount to 32 and not 16. I can’t stop scratching my head over this. Maybe I’ve got this wrong?

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Sorry but I finally got it. Every 4cm of each overlap is included in the 100 cm length of the overall wire. And therefore the additional overlap amount only to 4*4 = 16. Thank you for your explanation!
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Shikhar22
Five identical pieces of wire are soldered together end-to-end to form one longer wire, with the pieces overlapping by 4 cm at each joint. If the wire thus made is exactly 1 meter long, how long, in centimeters, is each of the identical pieces? (1 meter = 100 cm)
(A) 21.2 (B) 22 (C) 23.2 (D) 24 (E) 25.4

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This question is discussed in detail here: five-identical-pieces-of-wire-are-soldered-together-end-to-end-to-form-196688.html If any questions please post there. Hope it helps.

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