Nez wrote:

Any generous heart here to explain a solution to this math?

I'll greatly appreciate the needful.

We are here to learn.

The error has been corrected.

Bunuel is human.

can someone just give a solution cos I find that question a little confusing.

thanks in advance.

Sure look below.

You are given that the per gallon cost of gasoline varies from 0.96-1.12 $. The question now wants you to find the MAXIMUM possible difference between the least amount of money spent on gasoline and the largest amount of money spent i.e. to calculate max. trip cost - min. trip cost.

Mileage is given to be 16 to 24 miles per gallon ---> thus to travel 480 miles you will need gasoline in the range 480/24 to 480/16 --> 20 to 30 gallons.

Thus, for these 20-30 gallons of gasoline, you will need money (divide this task into 2 parts, 1 for 30 gallons and 2nd one for 20 gallons).

Case 1: for 30 gallons ---> you will end up spending 30*0.96 to 30*1.12$ ---> 28.8$ to 33.6$

Case 2: for 20 gallons ---> you will end up spending 20*0.96 to 20*1.12$ ---> 19.2$ to 22.4$

Thus, the maximum cost of the 480 mile trip = 33.6 $ and minimum = 19.2$ ---> difference = 33.6-19.2 = 14.4$. D is thus the correct answer.

Hope this helps.