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# GMAT Club Around The World!!! If square root of a = 3 and square root

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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
as a is positive and b is positive a = 9 b =16

so ex becomes 3 +4 / (underoot (9+16)) = 7/5

so ans is c ) 7/5
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
then a=9 et b=16

Then

3+4=7
7/V25=7/5

PUSH C
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
If $$\sqrt{a} = 3, and \sqrt{b} = 4$$, then a= 9 and b= 16

So, $$\frac{(\sqrt{a} + \sqrt{b}) }{ \sqrt{a + b}}$$ = $$\frac{( 3 + 4 )}{\sqrt{25}}$$ = $$\frac{7}{5}$$

Answer C.
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
√a =3, therefore, a=9 and √b =4, therefore, b=16,

therefore, √a + √b = 7 and √(a + b) = √ (9 + 16) = 5

So, the answer is C
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
Expert Reply
Bunuel wrote:
If $$\sqrt{a} = 3$$ and $$\sqrt{b} = 4$$, then $$\frac{\sqrt{a} + \sqrt{b} }{\sqrt{a+b}}=$$

A. 1
B. 8/7
C. 7/5
D. 12/5
E. 5

Happy New Year Australia/Western Australia!

We can get $$a = 9$$ and $$b = 16$$. Thus $$\sqrt{a + b} = \sqrt{9 + 16} = 5$$.

$$\frac{\sqrt{a} + \sqrt{b} }{\sqrt{a+b}}=\frac{3 + 4}{{5}} = \frac{7}{5}$$

Ans: C
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
IMO C

√a=3 => a = 9
√b=4 => b = 16

$$\frac{√a+√b}{√a+b}$$

= $$\frac{3 + 4 }{9+16}$$

= $$\frac{7}{√25}$$

= $$\frac{7}{5}$$
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
(√a+√b)/√(a+b) = (3+4)/√(9+16) = 7/5. Ans. C
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
IMO:C
Given rootA =3 => A =9
Also, root B = 4 => B=16

by plugging value in the given Equation will result in 7/5
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
Correct Answer C

√a=3 a = 9

and b√=4 b =16

(√a+√b) /√(a+b)= (3+4)/√(16+9) =7/5
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
Since , both the sides are positive we can square , without introducing any extraneous roots... so a = 9 and b = 16 .... final answer = 7/5
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
√a = 3
a = 9

√b = 4
b = 16

(√a + √b)/ √(a+b) = (3 + 4) / √(9+16) = 7/√25 = 7/5

So the correct answer will be C
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
Bunuel wrote:
If $$\sqrt{a} = 3$$ and $$\sqrt{b} = 4$$, then $$\frac{\sqrt{a} + \sqrt{b} }{\sqrt{a+b}}=$$

A. 1
B. 8/7
C. 7/5
D. 12/5
E. 5

Happy New Year Australia/Western Australia!

Dec 31 Event: GMAT Club Around The World!
(38 new questions posted every hour time zone on Dec 31!)

(a)^0.5 = 3 and (b)^0.5 = 4
Numerator = 7

Denominator = (3^2 + 4^2)^0.5 = (25)^0.5 = 5

Thus, 7/5 is the solution. IMO, option C is correct.
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
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Re: GMAT Club Around The World!!! If square root of a = 3 and square root [#permalink]
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