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09 Jul 2024, 05:34
Kudos
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Think of it this way-
Given- The first two containers have the same humidity percentage and there was a third container with different humidity percentage. The humidity percentage of the combined air was found to be 62%.
This is a weighted average problem and can be solved quickly using visualization.
Inference- Weight given to the first two containers will be twice the weight given to the last container. Thus the distance of the 2 sets of containers ((First set have container 1+2) and the second set has container 3) along 62% (can be written as 0.62 and is the average) can be visualized on a number line. For the two sets, the distance from 0.62 (average) will be in the ratio of 1:2 as the weights are in the ratio of 2:1-
Ratio of distance- <-------------1------------>:<----------2 ------->
First Two Container-----------------------------0.62--------------------Third Container
Plugin values and you will get the ratio of 1:2 is only satisfying in the below case-
Ratio of distance- <-------------1------------>:<----------2 ------->
First Two Container-----------------------------0.62--------------------Third Container
0.64 <-----------0.02----------> <---------0.04---> 0.58
Thus the final answer will be 0.64= 64% (First two containers) and 0.58=58% (Third container)
Given- The first two containers have the same humidity percentage and there was a third container with different humidity percentage. The humidity percentage of the combined air was found to be 62%.
This is a weighted average problem and can be solved quickly using visualization.
Inference- Weight given to the first two containers will be twice the weight given to the last container. Thus the distance of the 2 sets of containers ((First set have container 1+2) and the second set has container 3) along 62% (can be written as 0.62 and is the average) can be visualized on a number line. For the two sets, the distance from 0.62 (average) will be in the ratio of 1:2 as the weights are in the ratio of 2:1-
Ratio of distance- <-------------1------------>:<----------2 ------->
First Two Container-----------------------------0.62--------------------Third Container
Plugin values and you will get the ratio of 1:2 is only satisfying in the below case-
Ratio of distance- <-------------1------------>:<----------2 ------->
First Two Container-----------------------------0.62--------------------Third Container
0.64 <-----------0.02----------> <---------0.04---> 0.58
Thus the final answer will be 0.64= 64% (First two containers) and 0.58=58% (Third container)
09 Jul 2024, 05:36
Kudos
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first two container 3rd humidity
1 1 58%
2 2 59%
3 3 60%
4 4 64%
5 5 65%
1 1 58%
2 2 59%
3 3 60%
4 4 64%
5 5 65%
RenB
Joined: 13 Jul 2022
Last visit: 18 Nov 2025
Posts: 391
Given Kudos: 303
Location: India
Concentration: Finance, Nonprofit
Schools: Stanford '26 Wharton '26 (D) Kellogg '26 (II) Booth '26 (D) Yale '26 (S) CBS '26 (II) Darden '26 (S) HBS '26 (D) Ross '26 (II) LBS '26 (D) Tuck '26 (II)
GMAT Focus 1: 715 Q90 V84 DI82 
GPA: 3.74
WE:Corporate Finance (Consulting)
Schools: Stanford '26 Wharton '26 (D) Kellogg '26 (II) Booth '26 (D) Yale '26 (S) CBS '26 (II) Darden '26 (S) HBS '26 (D) Ross '26 (II) LBS '26 (D) Tuck '26 (II)
GMAT Focus 1: 715 Q90 V84 DI82
Posts: 391
09 Jul 2024, 05:43
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Bunuel
I read the question, then imagine 3 containers. Refer the attachment that follows.
Bunuel, KarishmaB, I'd love to know if there is a more efficient way to solve after the equation is formed or if the trial and error process can be streamlined better
Attachments
WhatsApp Image 2024-07-09 at 6.10.37 PM.jpeg [ 114.88 KiB | Viewed 707 times ]
