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09 Jul 2024, 05:34
Kudos
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Think of it this way-
Given- The first two containers have the same humidity percentage and there was a third container with different humidity percentage. The humidity percentage of the combined air was found to be 62%.
This is a weighted average problem and can be solved quickly using visualization.
Inference- Weight given to the first two containers will be twice the weight given to the last container. Thus the distance of the 2 sets of containers ((First set have container 1+2) and the second set has container 3) along 62% (can be written as 0.62 and is the average) can be visualized on a number line. For the two sets, the distance from 0.62 (average) will be in the ratio of 1:2 as the weights are in the ratio of 2:1-
Ratio of distance- <-------------1------------>:<----------2 ------->
First Two Container-----------------------------0.62--------------------Third Container
Plugin values and you will get the ratio of 1:2 is only satisfying in the below case-
Ratio of distance- <-------------1------------>:<----------2 ------->
First Two Container-----------------------------0.62--------------------Third Container
0.64 <-----------0.02----------> <---------0.04---> 0.58
Thus the final answer will be 0.64= 64% (First two containers) and 0.58=58% (Third container)
Given- The first two containers have the same humidity percentage and there was a third container with different humidity percentage. The humidity percentage of the combined air was found to be 62%.
This is a weighted average problem and can be solved quickly using visualization.
Inference- Weight given to the first two containers will be twice the weight given to the last container. Thus the distance of the 2 sets of containers ((First set have container 1+2) and the second set has container 3) along 62% (can be written as 0.62 and is the average) can be visualized on a number line. For the two sets, the distance from 0.62 (average) will be in the ratio of 1:2 as the weights are in the ratio of 2:1-
Ratio of distance- <-------------1------------>:<----------2 ------->
First Two Container-----------------------------0.62--------------------Third Container
Plugin values and you will get the ratio of 1:2 is only satisfying in the below case-
Ratio of distance- <-------------1------------>:<----------2 ------->
First Two Container-----------------------------0.62--------------------Third Container
0.64 <-----------0.02----------> <---------0.04---> 0.58
Thus the final answer will be 0.64= 64% (First two containers) and 0.58=58% (Third container)
09 Jul 2024, 05:36
Kudos
Bookmarks
first two container 3rd humidity
1 1 58%
2 2 59%
3 3 60%
4 4 64%
5 5 65%
1 1 58%
2 2 59%
3 3 60%
4 4 64%
5 5 65%
RenB
Joined: 13 Jul 2022
Last visit: 02 Mar 2026
Posts: 389
Given Kudos: 304
Location: India
Concentration: Finance, Nonprofit
Schools: Stanford '26 Wharton '26 (D) Booth '26 (D) Yale '26 (D) CBS '26 (A$$$) Darden '26 (WL) HBS '26 (D) Ross '26 (A$$$$) LBS '26 (D) Tuck '26 (A$$) Kellogg '26 (A)
GMAT Focus 1: 715 Q90 V84 DI82 
GPA: 3.74
WE:Corporate Finance (Consulting)
Schools: Stanford '26 Wharton '26 (D) Booth '26 (D) Yale '26 (D) CBS '26 (A$$$) Darden '26 (WL) HBS '26 (D) Ross '26 (A$$$$) LBS '26 (D) Tuck '26 (A$$) Kellogg '26 (A)
GMAT Focus 1: 715 Q90 V84 DI82
Posts: 389
09 Jul 2024, 05:43
Kudos
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Bunuel
I read the question, then imagine 3 containers. Refer the attachment that follows.
Bunuel, KarishmaB, I'd love to know if there is a more efficient way to solve after the equation is formed or if the trial and error process can be streamlined better
Attachments
WhatsApp Image 2024-07-09 at 6.10.37 PM.jpeg [ 114.88 KiB | Viewed 890 times ]
