Events & Promotions
| Last visit was: 20 Sep 2026, 19:11 |
It is currently 20 Sep 2026, 19:11 |
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included!
Sep 1810:00 AM IST
-11:00 PM IST
Start your journey with a fully customized action plan and work with a dedicated mentor to achieve a 735+ score.
Sep 2601:00 PM EDT
-04:00 PM EDT
Top scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included. Class starts Saturdays Sept. 26, 2026 - Dec. 19, 2026, 1:00pm-4:00pm ES
17 Jul 2024, 06:59
Kudos
Bookmarks
Distance covered on packed dirt (meters): 469
Distance covered on grass (meters): 1,876
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
78% (03:17) correct
22%
(03:38)
wrong
based on 1462
sessions
History
Date
Time
Result
Not Attempted Yet
An athlete training for a cross-country race covered three types of terrain in three distinct segments of a practice run; she ran across stretches of packed dirt, rocky scree, and grass, in that order. On packed dirt, she ran at an average speed of 201 meters per minute; she then rapidly slowed on the rocky scree, and covered the grass segment at an average speed of 100.5 meters per minute. The distance she covered on grass was four times the distance she covered on packed dirt, and it took her 21 minutes to cover both. On the table, select the distance she covered on both these terrains, in meters. Make only two selections, one in each column.
|
| Distance covered on packed dirt (meters) | Distance covered on grass (meters) | |
| 316.5 | ||
| 469 | ||
| 1,266 | ||
| 1,876 | ||
| 5,064 | ||
| 7,504 |
ShowHide Answer
Official Answer
Distance covered on packed dirt (meters): 469
Distance covered on grass (meters): 1,876
17 Jul 2024, 07:04
Kudos
Bookmarks
Bunuel
Experts' Global Explanation:
Let the speed of the athlete in the packed dirt and the grass be \(S_P\) and \(S_G\), respectively.
Let the distance covered on packed dirt and the grass be \(D_P\) and \(D_G\), respectively.
Let the time taken to cover packed dirt and the grass be \(T_P\) and \(T_G\), respectively.
\(S_P= 210\) meters per minute
\(S_G= 100.5\) meters per minute
Since the distance covered on grass was four times the distance covered on packed dirt: \(D_G= 4D_P\).
Since it took 21 minutes for the athlete to cover both the packed dirt and the grass: \(T_P+ T_G= 21\) minutes.
\(T_P+ T_G = (\frac{D_P}{ S_P}) + (\frac{D_G}{ S_G})\)
\(21 = (\frac{D_P}{ 201}) + (\frac{D_G}{ 100.5})\)
\(21 = (\frac{D_P}{ 201}) + (\frac{2D_G }{ 201})\)
\(21 = \frac{(D_P+ 2D_G)}{201}\)
\(21 =\frac{ (D_P+ 2 * 4D_P)}{201}\)
\(21 = \frac{(D_P+ 8D_P)}{201}\)
\(21 = \frac{(9D_P)}{201}\)
\(D_P = 469\) meters
\(D_G = 4D_P = 4 * 469 = 1,876\) meters.
17 Jul 2024, 07:29
Kudos
Bookmarks
An athlete training for a cross-country race covered three types of terrain in three distinct segments of a practice run; she ran across stretches of packed dirt, rocky scree, and grass, in that order. On packed dirt, she ran at an average speed of 201 meters per minute; she then rapidly slowed on the rocky scree, and covered the grass segment at an average speed of 100.5 meters per minute. The distance she covered on grass was four times the distance she covered on packed dirt, and it took her 21 minutes to cover both. On the table, select the distance she covered on both these terrains, in meters. Make only two selections, one in each column.
Distance covered on packed dirt (meters): 469
Distance covered on grass (meters): 1876
x/200,1 + 4x/100,5 = 21 minutes => x = 469 meters => 4x = 1876 meters
Distance covered on packed dirt (meters): 469
Distance covered on grass (meters): 1876
x/200,1 + 4x/100,5 = 21 minutes => x = 469 meters => 4x = 1876 meters
Oppenheimer1945
Joined: 16 Jul 2019
Last visit: 16 Sep 2026
Posts: 784
Given Kudos: 236
Location: India
Schools: INSEAD '26 (D) ISB '27 (D) IIMB '26 (A) IIMA '26 (A) HEC '26 (D) LBS '26 IESE '27 (D) Fuqua '27 (WL) Tepper '27 (WL)
GMAT Focus 1: 645 Q90 V76 DI80 
GPA: 7.81
Schools: INSEAD '26 (D) ISB '27 (D) IIMB '26 (A) IIMA '26 (A) HEC '26 (D) LBS '26 IESE '27 (D) Fuqua '27 (WL) Tepper '27 (WL)
GMAT Focus 1: 645 Q90 V76 DI80
Posts: 784
17 Jul 2024, 07:58
Kudos
Bookmarks
PD : speed=201 m/min
Time=T1
Dist1=201T1
Grass: speed=100.5 m/min
Time=T2
Dist=100.5 T2
Dist2=4Dist1
=> 8T1=T2
T1+T2=21;
T1=21/9=7/3 min, T2=56/3 min
Dist 1=469 m, Dist 2=1876 min
B, D
Time=T1
Dist1=201T1
Grass: speed=100.5 m/min
Time=T2
Dist=100.5 T2
Dist2=4Dist1
=> 8T1=T2
T1+T2=21;
T1=21/9=7/3 min, T2=56/3 min
Dist 1=469 m, Dist 2=1876 min
B, D
