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18 Jul 2024, 00:27
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Bunuel
469 1876
time taken on packed dirt = \(\frac{d}{201} \)minutes
time taken on grass = \(\frac{4d}{100.5 }\)minutes
\(\frac{d}{201} + \frac{4d}{100.5 } = 21\)
d = 469 --Packed Dirt
4d = 1876 -- Grass
18 Jul 2024, 00:55
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An athlete training for a cross-country race covered three types of terrain in three distinct segments of a practice run; she ran across stretches of packed dirt, rocky scree, and grass, in that order. On packed dirt, she ran at an average speed of 201 meters per minute; she then rapidly slowed on the rocky scree, and covered the grass segment at an average speed of 100.5 meters per minute. The distance she covered on grass was four times the distance she covered on packed dirt, and it took her 21 minutes to cover both. On the table, select the distance she covered on both these terrains, in meters. Make only two selections, one in each column.
Answer ->
Let speed across packed dirt and grass be s1 and s3 respectively.
Let distance of packed dirt and grass be d1 and d3 respectively.
Let time taken to cover packed dirt and grass be t1 and t3 respectively.
s1 = 201 m/min
s3 = 100.5 m/min
d3 = 4*d1
t1 + t3 =21
We know that speed = distance/time
d1/201 + d3/100.5 = 21
(d1 + 8d1)/201 = 21
d1 = 469
d3 = 469*4 = 1876
Hence, the distance she covered on packed dirt = 469 and on grass = 1876.
Answer ->
Let speed across packed dirt and grass be s1 and s3 respectively.
Let distance of packed dirt and grass be d1 and d3 respectively.
Let time taken to cover packed dirt and grass be t1 and t3 respectively.
s1 = 201 m/min
s3 = 100.5 m/min
d3 = 4*d1
t1 + t3 =21
We know that speed = distance/time
d1/201 + d3/100.5 = 21
(d1 + 8d1)/201 = 21
d1 = 469
d3 = 469*4 = 1876
Hence, the distance she covered on packed dirt = 469 and on grass = 1876.
18 Jul 2024, 00:55
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Distance covered on packed dirt (meters) : 469
Distance covered on grass (meters) : 1876
let d be distance covered on packed dirt; so 4d distance is covered on grass
d/201+4d/100.5 = 21
9d= 21x201
d=67x7 =469 = packed dirt distance
4d= 4X469 = 1876 = grass
Distance covered on grass (meters) : 1876
let d be distance covered on packed dirt; so 4d distance is covered on grass
d/201+4d/100.5 = 21
9d= 21x201
d=67x7 =469 = packed dirt distance
4d= 4X469 = 1876 = grass
