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SSWTtoKellogg
Joined: 06 Mar 2024
Last visit: 19 Nov 2025
Posts: 57
Given Kudos: 14
Location: India
Schools: Kellogg INSEAD Jan '26 Ross '26 Duke '26 Darden '26 Anderson '26 Tepper '26 Johnson '26 Kelley '26
GMAT Focus 1: 595 Q83 V78 DI77 
GMAT Focus 2: 645 Q87 V79 DI79
GPA: 8.8
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Schools: Kellogg INSEAD Jan '26 Ross '26 Duke '26 Darden '26 Anderson '26 Tepper '26 Johnson '26 Kelley '26
GMAT Focus 2: 645 Q87 V79 DI79
Posts: 57
09 Jul 2025, 04:05
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There are 7 numbers. Total = 7*30 =210.
We need Hmin =?
Let's take lower sides as high possible, which would be 24, 25, 26, 27; this sums up to 102.
210 - 102 = 108
Let's 108/3 = 36 ; we need 3 integers. That would be 35, 36, 37. D
We need Hmin =?
Let's take lower sides as high possible, which would be 24, 25, 26, 27; this sums up to 102.
210 - 102 = 108
Let's 108/3 = 36 ; we need 3 integers. That would be 35, 36, 37. D
09 Jul 2025, 04:09
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Bookmarks
Median is 27 and is in the middle
scores (x,y,z,27,u,v,w)
w will be minimum if x,y,z,u,v will be maximum
z can be 26 at most
y can be 25 at most
x can be 24 at most
x+y+z+27=24+25+26+27=102
The total scores add up to 30*7=210
u+v+w=210-102=108
maximun values for u and v if they are almost w:
108/3=36
u=35
v=36
w=37
The minimum possible value for the highest score is 37
Answer D
scores (x,y,z,27,u,v,w)
w will be minimum if x,y,z,u,v will be maximum
z can be 26 at most
y can be 25 at most
x can be 24 at most
x+y+z+27=24+25+26+27=102
The total scores add up to 30*7=210
u+v+w=210-102=108
maximun values for u and v if they are almost w:
108/3=36
u=35
v=36
w=37
The minimum possible value for the highest score is 37
Answer D
09 Jul 2025, 04:21
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Bookmarks
Option D is the correct answer.
Lets try to understand the information mentioned in the passage before solving it.
So the question starts by telling us that a class of seven students took a quiz in which marks were scored between 0 and 100 and all the seven students scored different marks in the quiz. The it further tells us that the average score of seven students is 30 and the median score is 27 and asks us what is the minimum possible value of highest score.
Now from the question we know the Median to be 27 respectively. Which would mean that a,b,c,27,x,y,z are the scores of the students.
And the Mean is given as 30 which would mean that a+b+c+27+x+y+z = 30*7 =>210.
The question also tells us that the values of a,b,c,x,y,z are all different.
So in order to find the minimum possible value of z i.e. the highest score first we need to maximize the value of a, b and c. So as the Median in this case is the 4th largest score i.e. 27 so the maximum values that a, b and c could take are 24, 25 and 26 respectively.
So, 24+25+26+27+x+y+z = 210
102+x+y+z = 210
x+y+z = 108
Now after solving this much we don't have any further information to proceed any further. So lets try using the values available in the option in order to get the answer.
Option A: z = 34
If z = 34 then the maximum values that x and y could take are 32 and 33 respectively.
=>32+33+34 ≠ 108
=>99 ≠ 108 Eliminated
Option B: z = 35
If z = 35 then the maximum values that x and y could take are 33 and 34 respectively.
=>33+34+35 ≠ 108
=>102 ≠ 108 Eliminated
Option C: z = 36
If z = 36 then the maximum values that x and y could take are 34 and 35 respectively.
=>34+35+36 ≠ 108
=>105 ≠ 108 Eliminated
Option D: z = 37
If z = 37 then the maximum values that x and y could take are 35 and 36 respectively.
=>35+36+37 ≠ 108
=>108 = 108 Selected
So from here we can conclude that the minimum value that highest score is 37 (Option D).
Lets try to understand the information mentioned in the passage before solving it.
So the question starts by telling us that a class of seven students took a quiz in which marks were scored between 0 and 100 and all the seven students scored different marks in the quiz. The it further tells us that the average score of seven students is 30 and the median score is 27 and asks us what is the minimum possible value of highest score.
Now from the question we know the Median to be 27 respectively. Which would mean that a,b,c,27,x,y,z are the scores of the students.
And the Mean is given as 30 which would mean that a+b+c+27+x+y+z = 30*7 =>210.
The question also tells us that the values of a,b,c,x,y,z are all different.
So in order to find the minimum possible value of z i.e. the highest score first we need to maximize the value of a, b and c. So as the Median in this case is the 4th largest score i.e. 27 so the maximum values that a, b and c could take are 24, 25 and 26 respectively.
So, 24+25+26+27+x+y+z = 210
102+x+y+z = 210
x+y+z = 108
Now after solving this much we don't have any further information to proceed any further. So lets try using the values available in the option in order to get the answer.
Option A: z = 34
If z = 34 then the maximum values that x and y could take are 32 and 33 respectively.
=>32+33+34 ≠ 108
=>99 ≠ 108 Eliminated
Option B: z = 35
If z = 35 then the maximum values that x and y could take are 33 and 34 respectively.
=>33+34+35 ≠ 108
=>102 ≠ 108 Eliminated
Option C: z = 36
If z = 36 then the maximum values that x and y could take are 34 and 35 respectively.
=>34+35+36 ≠ 108
=>105 ≠ 108 Eliminated
Option D: z = 37
If z = 37 then the maximum values that x and y could take are 35 and 36 respectively.
=>35+36+37 ≠ 108
=>108 = 108 Selected
So from here we can conclude that the minimum value that highest score is 37 (Option D).
Bunuel
