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21 Dec 2016, 04:57
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
80% (00:39) correct
20%
(00:47)
wrong
based on 89
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How many different arrangements of A, B, C, D, and E are possible where A is either leftmost or rightmost?
A. 6
B. 12
C. 24
D. 48
E. 60
A. 6
B. 12
C. 24
D. 48
E. 60
21 Dec 2016, 05:25
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Bookmarks
We’ll start with the most restrictive element: A
A has only 2 options for placement. After A was placed, B C D E can be arranged in 4! ways
\(2*4! = 48\)
Answer D
A has only 2 options for placement. After A was placed, B C D E can be arranged in 4! ways
\(2*4! = 48\)
Answer D
saurabhsavant
Joined: 27 Aug 2016
Last visit: 09 Nov 2017
Posts: 74
Given Kudos: 149
Location: India
Schools: HEC Montreal '21
GMAT 1: 670 Q47 V37
GPA: 3
WE:Engineering (Energy)
27 Dec 2016, 10:55
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Bunuel
How many different arrangements of A, B, C, D, and E are possible where A is either leftmost or rightmost?
A. 6
B. 12
C. 24
D. 48
E. 60
A. 6
B. 12
C. 24
D. 48
E. 60
With A fixed at 1st position rest four letters can b arranged in 4! ways, similarly, with A fixed at last position others can be arranged in 4! ways...therefore total ways = 4! + 4! = 48..hence D
