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CAMANISHPARMAR
How many zeros does 250! end with?

A. 60
B. 62
C. 64
D. 68
E. 70
\(\frac{250}{5} = 50\)
\(\frac{50}{5} = 10\)
\(\frac{10}{5} = 2\)

So, 250! must end in 62 zeroes, answer must be (B)
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Hello,

Can somebody help me understand why we are searching for the number of "5's" in 250!? I had taken a similar approach but was looking for the numbers which were factors of 10 (250,245,242...) and arrived at 50 "10's". What is the reason for adding the factors 250/5^2 and 250/5^3?

Thank you!!!

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vlfalk
Hello,

Can somebody help me understand why we are searching for the number of "5's" in 250!? I had taken a similar approach but was looking for the numbers which were factors of 10 (250,245,242...) and arrived at 50 "10's". What is the reason for adding the factors 250/5^2 and 250/5^3?

Thank you!!!

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Hi,

To count number of trailing zeroes, we actually check the divisibility by 10. Since 10 has prime factors 5 and 2, on checking for factors of 5 in 250!, equal number of factors of 2 are also counted.

For more understanding on this concept, refer to GC Math book.
https://gmatclub.com/forum/gmat-math-bo ... 30609.html
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