Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: If 1/55 < x < 1/22 and 1/33 < x < 1/11, then which of the following [#permalink]

Show Tags

23 Apr 2017, 17:41

stonecold wrote:

If \(\frac{1}{55}<x<\frac{1}{22}\) and \(\frac{1}{33}<x<\frac{1}{11}\) , then which of the following could be the value of x?

(I)\(\frac{1}{54}\)

(II)\(\frac{1}{23}\)

(III)\(\frac{1}{12}\)

A)Only I B)Only II C)I and II D)II and III E)I,II,III

Source => NOVA.

The most efficient way to solve this problem is to just cross multiply the denominators all across the expression- for example

[1/55] < [1/23] [23/(55)(23)] < [55/(55)(23)]

and then

1/23 < 1/22 22/(23)(22) < 23/(23)(22)

The most efficient way, then, is to just compare the denominators

* once you cross multiply two fractions such as - [23/(55)(23)] < [55/(55)(23)] - do not cross multiply again by the next fraction for example [23/(55)(23)] < [55/(55)(23)] cross multiplied by 1/22

Re: If 1/55 < x < 1/22 and 1/33 < x < 1/11, then which of the following [#permalink]

Show Tags

15 May 2017, 03:34

I solved it the traditional way (taking LCM and comparing each fraction option with the ranges given and it took me almost 3 mins to conclude the right answer. Request you to advise the best approach to solve such problems.

Nunuboy1994 : I could not understand the cross-multiplication approach you are suggesting

.............<---------------------------- x --------------------------> and ................................................<---------------------------- x ---------------------->

1/33 < x < 1/22 So all values such as 1/23, 1/24, 1/25.... 1/32 will lie within this range.

Re: If 1/55 < x < 1/22 and 1/33 < x < 1/11, then which of the following [#permalink]

Show Tags

15 May 2017, 05:26

If 155<x<122155<x<122 and 133<x<111133<x<111 , then which of the following could be the value of x?

Cond 1) 155<x<122155<x<122

Cond 2) 133<x<111133<x<111

(I)154154 it cant satisfy both conditions

(II)123123

(III)112112 it cant satisfy both conditions

A)Only I B)Only II C)I and II D)II and III E)I,II,III
_________________

_________________ Rules for posting in verbal Gmat forum, read it before posting anything in verbal forum Giving me + 1 kudos if my post is valuable with you

The more you like my post, the more you share to other's need.

“The great secret of true success, of true happiness, is this: the man or woman who asks for no return, the perfectly unselfish person, is the most successful.” -Swami Vivekananda

Re: If 1/55 < x < 1/22 and 1/33 < x < 1/11, then which of the following [#permalink]

Show Tags

08 Aug 2017, 09:07

1

This post received KUDOS

For me the best way to resolve this was to write the numbers with negative exponents 1/55 = (55)^-1 1/33 = (33)^-1 1/22 = (22)^-1 1/11 = (11)^-1

So if 1/55<x<1/22 and 1/33<x<1/11 then

------55---------------22-------------> ------------33---------------11-------> range that covers both conditions is (33)^-1<x<(22)^-1 then only B (23)^1 satisfies it