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30 Nov 2015, 08:45
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The answer is a.
(i) Given, x>0
Since x is positive, we can rewrite the inequality as
3x >|4y|
3x > 4|y|
x > (4/3) |y|
x > 1.something*|y|
Clearly we can conclude that x>y.
Hence sufficient.
(ii) y>0
Given y is positive and hence the inequality becomes
|3x|> 4y
|x|> (4/3)*y
|x|> 1.something*y
This can be true for a negative value of x, where x<y and also for a positive value of x where x>y.
Hence insufficient.
(i) Given, x>0
Since x is positive, we can rewrite the inequality as
3x >|4y|
3x > 4|y|
x > (4/3) |y|
x > 1.something*|y|
Clearly we can conclude that x>y.
Hence sufficient.
(ii) y>0
Given y is positive and hence the inequality becomes
|3x|> 4y
|x|> (4/3)*y
|x|> 1.something*y
This can be true for a negative value of x, where x<y and also for a positive value of x where x>y.
Hence insufficient.
30 Nov 2015, 10:46
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|3x|>|4y|
So, to make this true, it has to be |x|>|y|
Now st1: x>0,
as 3 is multiplied with x, and 4 is with y, x has to be bigger than y. even x will be > |y|.
For St 2: y>0,
lets say y is 6(and positive)... so 4y is 24... to satisfy initial condition, |x| has to be > 8, so, x can be -9 or +9(etc)... So, insufficient.
Thus A
So, to make this true, it has to be |x|>|y|
Now st1: x>0,
as 3 is multiplied with x, and 4 is with y, x has to be bigger than y. even x will be > |y|.
For St 2: y>0,
lets say y is 6(and positive)... so 4y is 24... to satisfy initial condition, |x| has to be > 8, so, x can be -9 or +9(etc)... So, insufficient.
Thus A
30 Nov 2015, 18:43
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Ans:A
Since the question has mod | | - it is obvious that the actual value of x will always be greater than y for the inequality to work.
The trick is to figure out the sign.
1. if x>0 - Sufficient
x=1, 3x = 3. For the inequality to work - y has to be 0. any other value for y will make |4y| > 3.
2. y>0. Not sufficient.
for y=5, x can be -7 or 7. in both cases |3x| > 20. Hence not sufficient.
Since the question has mod | | - it is obvious that the actual value of x will always be greater than y for the inequality to work.
The trick is to figure out the sign.
1. if x>0 - Sufficient
x=1, 3x = 3. For the inequality to work - y has to be 0. any other value for y will make |4y| > 3.
2. y>0. Not sufficient.
for y=5, x can be -7 or 7. in both cases |3x| > 20. Hence not sufficient.
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