Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jul 1011:00 AM PDT
-11:00 AM PDT
In our conversation, Kishore talks about how strategically he used data analytics to identify high impact areas to focus on as well as his early morning study routine (3 AM prep!) that optimized his GMAT preparation.- Jun 30
08:00 AM PDT
-11:59 PM PDT
Join us June 30th for 2 weeks of GMAT questions (just 8 per day) to help with your prep and to compete with your fellow GMAT Clubbers for a chance to win a prize fund of $30,000 for you and your team-mates! 
Jul 0901:00 PM EDT
-02:00 PM EDT
More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.
Jul 1206:30 AM PDT
-08:30 AM PDT
Join our webinar to master GMAT RC Main Point Questions! Learn effective strategies to decipher passage themes and purposes. Senior Verbal Expert- Sunita Singhvi will equip you with tools to navigate complexities and avoid common traps set by the GMAT.
Jul 1211:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.
Jul 1311:00 AM EDT
-12:30 PM EDT
Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Jul 1508:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Jul 1611:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
Updated on: 22 Apr 2023, 01:23
Originally posted by heyholetsgo on 18 Aug 2010, 10:06.
Last edited by Bunuel on 22 Apr 2023, 01:23, edited 3 times in total.
Last edited by Bunuel on 22 Apr 2023, 01:23, edited 3 times in total.
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
57% (02:00) correct
43%
(02:18)
wrong
based on 819
sessions
History
Date
Time
Result
Not Attempted Yet
If 8x > 4 + 6x, what is the value of the integer x?
(1) 6 – 5x > -13
(2) 3 – 2x < -x + 4 < 7.2 – 2x
(1) 6 – 5x > -13
(2) 3 – 2x < -x + 4 < 7.2 – 2x
Could anybody tell me when it is appropriate to add up equations? That's what I did and it didn't work...
18 Aug 2010, 10:18
Kudos
Bookmarks
If 8x > 4 + 6x, what is the value of the integer x?
First, note that we are given that x is an integer.
Next, simplify the given inequality:
(1) \(6-5x>-13\);
Since x is an integer and \(x > 2\), then \(x = 3\). Sufficient.
(2) \(3-2x<-x+4<7.2-2x\)
Consider only the following part:
Since x is an integer and \(x > 2\), then \(x = 3\). Sufficient.
Answer: D.
There is no need to add inequalities in this case. However, if you are interested:
You can only add inequalities when their signs are in the same direction:
If \(a > b\) and \(c > d\) (signs in the same direction: \( > \) and \( > \)) --> \(a + c > b + d\).
You can only apply subtraction when their signs are in the opposite directions:
If \(a > b\) and \(c < d\) (signs in opposite direction: \( > \) and \( < \)) --> \(a - c > b - d\) (take the sign of the inequality you subtract from).
Hope it helps.
First, note that we are given that x is an integer.
Next, simplify the given inequality:
- \(8x>4+6x\);
\(2x>4\);
\(x>2\).
(1) \(6-5x>-13\);
- \(19>5x\);
\(3.8>x\).
Since x is an integer and \(x > 2\), then \(x = 3\). Sufficient.
(2) \(3-2x<-x+4<7.2-2x\)
Consider only the following part:
- \(-x+4<7.2-2x\);
\(x<3.2\)
Since x is an integer and \(x > 2\), then \(x = 3\). Sufficient.
Answer: D.
heyholetsgo
Could anybody tell me when it is appropriate to add up equations? That's what I did and it didn't work...
There is no need to add inequalities in this case. However, if you are interested:
You can only add inequalities when their signs are in the same direction:
If \(a > b\) and \(c > d\) (signs in the same direction: \( > \) and \( > \)) --> \(a + c > b + d\).
- Example: \(3 < 4\) and \(2 < 5\) --> \(3 + 2 < 4 + 5\).
You can only apply subtraction when their signs are in the opposite directions:
If \(a > b\) and \(c < d\) (signs in opposite direction: \( > \) and \( < \)) --> \(a - c > b - d\) (take the sign of the inequality you subtract from).
- Example: \(3 < 4\) and \(5 > 1\) --> \(3 - 5 < 4 - 1\).
Hope it helps.
General Discussion
19 Aug 2010, 00:55
Kudos
Bookmarks
Bunuel
heyholetsgo
If 8x > 4 + 6x, what is the value of the integer x?
(1) 6 – 5x > -13
(2) 3 – 2x < -x + 4 < 7.2 – 2x
Could anybody tell me when it is appropriate to add up equations? That's what I did and it didn't work...
(1) 6 – 5x > -13
(2) 3 – 2x < -x + 4 < 7.2 – 2x
Could anybody tell me when it is appropriate to add up equations? That's what I did and it didn't work...
Given: \(x=integer\) and \(8x>4+6x\) --> \(2x>4\) --> \(x>2\). Question: \(x=?\)
(1) \(6-5x>-13\) --> \(19>5x\) --> \(\frac{19}{5}=3.8>x\) --> as \(x=integer\) and \(x>2\), then \(x=3\). Sufficient.
(2) \(3-2x<-x+4<7.2-2x\) --> take only the following part: \(-x+4<7.2-2x\)--> \(x<3.2\) --> as \(x=integer\) and \(x>2\), then \(x=3\). Sufficient.
Answer: D.
So no need to add inequality in this case. But if you are interested:
You can only add inequalities when their signs are in the same direction:
If \(a>b\) and \(c>d\) (signs in same direction: \(>\) and \(>\)) --> \(a+c>b+d\).
Example: \(3<4\) and \(2<5\) --> \(3+2<4+5\).
You can only apply subtraction when their signs are in the opposite directions:
If \(a>b\) and \(c<d\) (signs in opposite direction: \(>\) and \(<\)) --> \(a-c>b-d\) (take the sign of the inequality you subtract from).
Example: \(3<4\) and \(5>1\) --> \(3-5<4-1\).
Hope it helps.
Hi,
can you explain stmt B please, why is that only the second part is considered?
