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Couldn't figure out a way to do this without plugging in numbers. Anyone understand this from a theory perspective?
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I did it without plugging in.
I cross multiplied the inequality and got:
b(a-2p)>a(b-2p) <-----both a AND b are negative leaving the inequality sign unchanged
ab-2bp > ab - 2ap <----subtract ab from both sides
-2bp > -2ap <----- divide by (-2)
So, is bp<ap?

(1) p>0, this does not give enough information to answer the question because we don't know anything about b and a.

(2) a<b, this does not give us enough info, because it matters if p is positive or negative.

(1)+(2) Sufficient, the answer to the question (is bp<ap?) is no.
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viktorija
I did it without plugging in.
I cross multiplied the inequality and got:
b(a-2p)>a(b-2p) <-----both a AND b are negative leaving the inequality sign unchanged
ab-2bp > ab - 2ap <----subtract ab from both sides
-2bp > -2ap <----- divide by (-2)
So, is bp<ap?

(1) p>0, this does not give enough information to answer the question because we don't know anything about b and a.

(2) a<b, this does not give us enough info, because it matters if p is positive or negative.

(1)+(2) Sufficient, the answer to the question (is bp<ap?) is no.

Interesting approach. I thought about cross multiplying but didn't because without knowing p, we wouldn't know if the value (a-2p) or (b-2p) is positive or negative. It is also possible that one is positive and one is negative.
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jwang27
viktorija
I did it without plugging in.
I cross multiplied the inequality and got:
b(a-2p)>a(b-2p) <-----both a AND b are negative leaving the inequality sign unchanged
ab-2bp > ab - 2ap <----subtract ab from both sides
-2bp > -2ap <----- divide by (-2)
So, is bp<ap?

(1) p>0, this does not give enough information to answer the question because we don't know anything about b and a.

(2) a<b, this does not give us enough info, because it matters if p is positive or negative.

(1)+(2) Sufficient, the answer to the question (is bp<ap?) is no.

Interesting approach. I thought about cross multiplying but didn't because without knowing p, we wouldn't know if the value (a-2p) or (b-2p) is positive or negative. It is also possible that one is positive and one is negative.

When I cross multiplied, I basically needed to know if b is negative (which I knew because it's given) and if (b-2p) is negative. That's important to know because at first we multiply by one denominator which is b and then we multiply by the second which is (b-2p). So, I tried both and I got:
is bp>ap, when (b-2p) is negative
OR is bp<ap, when (b-2p) is positive.
The question stays the same though, because we still need to find which is bigger.

That was the logic behind, but I'm not sure if it's correct.

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