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If a, b, and c are integers, is the number divisible by 3?

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If a, b, and c are integers, is the number divisible by 3? [#permalink]

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New post 18 Jan 2009, 19:47
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If a, b, and c are integers, is the number divisible by 3?

(1) a + b is divisible by 3.
(2) c is divisible by 3.

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Re: 1000 DS [#permalink]

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New post 18 Jan 2009, 20:47
Some thing is missing in the question part. Which number is the one to find whether it is divisible by 3 or not?

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Re: 1000 DS [#permalink]

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New post 19 Jan 2009, 07:50
Sorry...Here is the Question again.....

If a, b, and c are integers, is the number 3(a+b)-c divisible by 3?

(1) a + b is divisible by 3.
(2) c is divisible by 3.

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Re: 1000 DS [#permalink]

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New post 19 Jan 2009, 08:01
vicky81 wrote:
Sorry...Here is the Question again.....

If a, b, and c are integers, is the number 3(a+b)-c divisible by 3?

(1) a + b is divisible by 3.
(2) c is divisible by 3.


Should be B.

If c=3x, 3(a+b)-c= 3(a+b)-3x=3(a+b-x)

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Re: 1000 DS [#permalink]

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New post 19 Jan 2009, 08:08
Lets assume....

a=1,b=0 and c=3 ( as a,b and C are integers)

so 3(a+b)-c = 3(1+0) -3 = 0 ...0 is not divisible by 3.

I think the answer should be C ....

What do u say ??

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Re: 1000 DS [#permalink]

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New post 19 Jan 2009, 09:02
vicky81 wrote:
Lets assume....

a=1,b=0 and c=3 ( as a,b and C are integers)

so 3(a+b)-c = 3(1+0) -3 = 0 ...0 is not divisible by 3.

I think the answer should be C ....

What do u say ??

vicky, I believe zero is evenly divisible by 3 - every number is, except zero itself.

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Re: 1000 DS [#permalink]

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New post 19 Jan 2009, 09:13
IMO B.

Here is a simple rule worth remembering. For any 2 integers, a and b,

case 1, if a is a multiple of n, b is a multiple of n, then a + b or a - b will be a multiple of n.
case 1, if a is a multiple of n, b is NOT a multiple of n, then a + b or a - b will NOT be a multiple of n.
case 1, if a is NOT a multiple of n, b is NOT a multiple of n, then a + b or a - b CAN be a multiple of n.

The question stem is - Is 3(a+b)-c divisible by 3? Here first term is 3(a+b) and second term is c. First term is clearly multple of 3. So to answer the question, we need to know whether c is divisble by 3. And based on the above rules we can say whether the number in question is divisible by 3.

Stmt 1 - a + b is divisible by 3. This is immaterial since we know that first term is already divisible by 3. Nothing is mentioned abt c. Hence In sufficient.

Stmt 2 - c is divisible by 3. This clue is sufficient now that both the first and the second terms are divisible by 3. Hence the number is question is divisible by 3. Sufficient.

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Re: 1000 DS [#permalink]

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New post 19 Jan 2009, 09:49
If a, b, and c are integers, is the number 3(a+b)-c divisible by 3?

(1) a + b is divisible by 3.
(2) c is divisible by 3.

This is a yes/no question.
since 3(a+b) is a multiple of 3 ..it is divisible by 3

so if c is divisible then the answer would be yes
if c is not divisible by 3 then the answer would be no.

stmt 1: is not sufficient as theres no information about c..so the answer could be Yes or No.

stmt 2: is sufficient as it says c is divisible by 3 so the answer is a YES.


answer is B.


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Re: 1000 DS [#permalink]

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New post 19 Jan 2009, 09:58
vicky81 wrote:
Sorry...Here is the Question again.....

If a, b, and c are integers, is the number 3(a+b)-c divisible by 3?

(1) a + b is divisible by 3.
(2) c is divisible by 3.

1 is not providing additional info.
2 is sufficient.
Hence, B.
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Re: 1000 DS [#permalink]

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New post 20 Jan 2009, 16:44
If a, b, and c are integers, is the number 3(a+b)-c divisible by 3?

(1) a + b is divisible by 3.
(2) c is divisible by 3.

Lets check the equation in question.

there are two parts of the equation. 3(a+b) and then c.

now 3(a+b) will always be divisible by 3. as it represents some thing like 3x. now for this equation to be divisible by 3 we only need to know whether c is divisible by 3 or not. this information is amply supplied by statement 2.

Hence the answer is B.

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Re: 1000 DS [#permalink]

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New post 21 Jan 2009, 03:40
milind1979 wrote:
If a, b, and c are integers, is the number 3(a+b)-c divisible by 3?

(1) a + b is divisible by 3.
(2) c is divisible by 3.

Lets check the equation in question.

there are two parts of the equation. 3(a+b) and then c.

now 3(a+b) will always be divisible by 3. as it represents some thing like 3x. now for this equation to be divisible by 3 we only need to know whether c is divisible by 3 or not. this information is amply supplied by statement 2.

Hence the answer is B.


The answer is B, definitely.

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Re: 1000 DS   [#permalink] 21 Jan 2009, 03:40
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If a, b, and c are integers, is the number divisible by 3?

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