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11 Dec 2019, 04:33
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If a, b & c are integers and a < b < c. Are a, b, c consecutive integers?
(1) The median of {a!, b!, c!} is an odd number.
(2) c! is a prime number.
A. Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
B. Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
D. EACH statement ALONE is sufficient
E. Statements (1) and (2) TOGETHER are NOT sufficient
This question is from the GC Diagnostic Test Ver 6.2 - I had to create a new thread as the other one was locked (Link: gmat-diagnostic-test-question-79347.html).
I have a doubt in the solution to the above question.
(1) says that the median of \((a!, b!, c!)\) is an odd number. This implies that \(a,b,c\) are non-negative integers. As the median \((b!) = 1\), the only possible case this can happen is \(a=0, b=1, c=2\). I don't understand why we are taking the case that \(b=0\), as that would mean \(a\) is a negative number and we're given in the statement that median exists for \(a!, b!\) and \(c!\), which means it has to be defined.
Someone kindly clarify this. Thanks.
(1) The median of {a!, b!, c!} is an odd number.
(2) c! is a prime number.
A. Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
B. Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
D. EACH statement ALONE is sufficient
E. Statements (1) and (2) TOGETHER are NOT sufficient
This question is from the GC Diagnostic Test Ver 6.2 - I had to create a new thread as the other one was locked (Link: gmat-diagnostic-test-question-79347.html).
I have a doubt in the solution to the above question.
(1) says that the median of \((a!, b!, c!)\) is an odd number. This implies that \(a,b,c\) are non-negative integers. As the median \((b!) = 1\), the only possible case this can happen is \(a=0, b=1, c=2\). I don't understand why we are taking the case that \(b=0\), as that would mean \(a\) is a negative number and we're given in the statement that median exists for \(a!, b!\) and \(c!\), which means it has to be defined.
Someone kindly clarify this. Thanks.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
11 Dec 2019, 04:41
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Discussed here: d01-183481.html
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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