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jwam2
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I see but still not convinced on having a negative root.

Source: MGMAT Chapter 5, Page 79 - In Action problem #2)

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jwamala
I see but still not convinced on having a negative root.

Source: MGMAT Chapter 5, Page 79 - In Action problem #2)

Posted from my mobile device

As per GMAT,
\(\sqrt{9}= 3\) and not -3..
only if it is given \(\sqrt{9}= |3|\), you take two values 3 and -3..

there must be some thing else given too to take -ive root as an option..
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I agree with you; that's why I posted the question.

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jwamala
I see but still not convinced on having a negative root.

Source: MGMAT Chapter 5, Page 79 - In Action problem #2)

Posted from my mobile device

As per GMAT,
\(\sqrt{9}= 3\) and not -3..
only if it is given \(\sqrt{9}= |3|\), you take two values 3 and -3..

there must be some thing else given too to take -ive root as an option..


Is this only as per GMAT or mathematics in General? bunuel?
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chetan2u
jwamala
I see but still not convinced on having a negative root.

Source: MGMAT Chapter 5, Page 79 - In Action problem #2)

Posted from my mobile device

As per GMAT,
\(\sqrt{9}= 3\) and not -3..
only if it is given \(\sqrt{9}= |3|\), you take two values 3 and -3..

there must be some thing else given too to take -ive root as an option..


Is this only as per GMAT or mathematics in General? bunuel?

When the GMAT provides the square root sign for an even root, such as \(\sqrt{x}\) or \(\sqrt[4]{x}\), then the only accepted answer is the positive root.

That is, \(\sqrt{25}=5\), NOT +5 or -5. Even roots have only a positive value on the GMAT.

In contrast, the equation \(x^2=25\) has TWO solutions, +5 and -5.
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