Solution:Given: jk ≠ 0 (j, k) lies in the xy-coordinate system.

To find: In which quadrant does (j, k) lie?

For to find out this we should know that, the polarities of the point (j,k) in different quadrants.

QUADRANT I = +, +

QUADRANT II = -, +

QUADRANT III = -,-

QUADRANT IV = +,-

Analysis of statement 1: jk < 0The product of j and k should give us the value which is less than 0. This means that, one of the values either “j” or “k” must be negative and other must be positive. (As we get product of positive and negative as negative itself. )

That means, the point (j, k) lie either in 2nd quadrant (where “j” is negative and “k” is positive) or (j,k) lie in 4th quadrant (where “j” is positive and “k” is negative).

Hence statement 1 is insufficient to answer. We can eliminate the options A and D.

Analysis of statement 2: j + k > 0This case is definitely valid for I quadrant. Not at all valid for III quadrant as both j and k will be negative.

Cannot comment about II and IV quadrant. For example: The points (-4, 8) and (8, -4). So the point (j,k) can lie in either of the quadrants.

Hence statement 2 is insufficient to answer. So we can eliminate option B.

Combining the statements 1 and 2: we get:From statement 1, we know that the point (j,k) can lie in 2nd or 4th quadrant.

From statement 2, we know the point (j,k) can lie in 1st , 2nd or in 4th quadrant.

Even after combining we get that point (j,k) can lie in 2nd or in 4th quadrant.

Hence insufficient.

So the correct answer option is “E”.

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