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Bunuel
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Forget Conventional Methods here(it sounds cool when i say that eh?)
Use the property => K and K^n always have the same exact prime factors.
Statement1=> m=2 => NO
m=10=> YES
insuff
Statement 2 => From this statement we can say that m must have 5 as its prime.
Hence m^5 must be divisible by 5.
Suff

Hence B
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Bunuel
If m is an integer, is m^4 divisible by 5?

(1) m is divisible by 2
(2) m^3 is divisible by 125


1. m is divisible by 2 i.e. m is even number which can not be divisible by 5(odd number)
IN SUFFICIENT

2. m^3 is divisible by 125
as 5 is a factor of 125, so m^4 must be divisible by 5.
SUFFICIENT

ANSWER=B


ALL THE VERY BEST FOR YOUR PREPERATION.
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Bunuel
If m is an integer, is m^4 divisible by 5?

(1) m is divisible by 2
(2) m^3 is divisible by 125

Statement 1

No because m could be 10, 4 or a bunch of other numbers

Statement 2

m^3/5^3 = integer so

m^3 x m/5 = integer

B
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