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Updated on: 28 Jun 2020, 13:17
Originally posted by coreyander on 28 Jun 2020, 13:13.
Last edited by Bunuel on 28 Jun 2020, 13:17, edited 1 time in total.
Last edited by Bunuel on 28 Jun 2020, 13:17, edited 1 time in total.
Renamed the topic.
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C
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If \(n\neq{0}\) and \(\frac{x}{n^2}=4-\frac{3n^2-5n}{n^2}\), then what is the value of x in terms of n?
A) \(n^2 – 5n\)
B) \(–n^2 + 5n\)
C) \(n^2 + 5n\)
D) \(4 – 3n^2 – 5n\)
E) \(4 – 3n^2 + 5n\)
A) \(n^2 – 5n\)
B) \(–n^2 + 5n\)
C) \(n^2 + 5n\)
D) \(4 – 3n^2 – 5n\)
E) \(4 – 3n^2 + 5n\)
yashikaaggarwal
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28 Jun 2020, 13:21
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X/N^2 = 4-{(3n^2-5n)/n^2}
X/N^2 = 4n^2-3n^2+5n/n^2
X/N^2 = n^2+5n/n^2
X = n^2+5n
Answer is C
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X/N^2 = 4n^2-3n^2+5n/n^2
X/N^2 = n^2+5n/n^2
X = n^2+5n
Answer is C
Posted from my mobile device
28 Jun 2020, 13:31
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If n ≠ 0 and \(x/n^2 = 4− (3n^2−5n)/n^2\)
Let n be 2
Then \(x/4 = 4− (3*4−5*2)/4\)
\(x/4 = 4− (2/4)\)
\(x = 16− 2\)
x= 14
Now Put n = 2 in the Options:
A) n^2–5n
For N = 2 Value is -6. ELIMINATED
B) –n^2+5n
For N = 2 Value is +6. ELIMINATED
C) n^2+5n
For N = 2 Value is 14, Lets keep and check D & E to be sure.
D) 4–3n^2–5n
For N = 2 Value is -18. ELIMINATED
E) 4–3n^2+5n
For N = 2 Value is 2. ELIMINATED
ANSWER IS C
Let n be 2
Then \(x/4 = 4− (3*4−5*2)/4\)
\(x/4 = 4− (2/4)\)
\(x = 16− 2\)
x= 14
Now Put n = 2 in the Options:
A) n^2–5n
For N = 2 Value is -6. ELIMINATED
B) –n^2+5n
For N = 2 Value is +6. ELIMINATED
C) n^2+5n
For N = 2 Value is 14, Lets keep and check D & E to be sure.
D) 4–3n^2–5n
For N = 2 Value is -18. ELIMINATED
E) 4–3n^2+5n
For N = 2 Value is 2. ELIMINATED
ANSWER IS C
