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The value of n is defined as an expression involving factorials, as, n = \(\frac{25! }{ 20!}\)

By definition of factorials, 25! can be broken up as 25! = 25 * 24 * 23 * 22 * 21 * 20!

Therefore, n =\( \frac{25 * 24 * 23 * 22 * 21 * 20! }{ 20!}\)

The 20! cancels out and consequently, n = 25 * 24 * 23 * 22 * 21.

Prime factorising the constituents of n, n = \(2^4\) * \(3^2\) * \(5^2\) * 7 * 11 * 23

Prime factorising the numbers given in the answer options,
48 = \(2^4\) * 3
66 = 2 * 3 * 11
96 = \(2^5\) * 3
100 = \(2^2\) * \(5^2\)
385 = 5 * 7 * 11

It can be seen that 96 cannot divide n fully since the highest power of 2 present in n is 4. Therefore, \(\frac{n }{ 96}\) will not be an integer.

The correct answer option is C.
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