Last visit was: 12 Dec 2024, 11:28 It is currently 12 Dec 2024, 11:28
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 12 Dec 2024
Posts: 97,847
Own Kudos:
685,359
 []
Given Kudos: 88,255
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 97,847
Kudos: 685,359
 []
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
mohshu
Joined: 21 Mar 2016
Last visit: 26 Dec 2019
Posts: 448
Own Kudos:
Given Kudos: 103
Products:
Posts: 448
Kudos: 127
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
pradeepmaria
Joined: 11 May 2015
Last visit: 31 Oct 2021
Posts: 31
Own Kudos:
Given Kudos: 21
Location: United States
Concentration: Strategy, Operations
GPA: 3.44
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
K_Leon
Joined: 21 Jun 2017
Last visit: 09 Sep 2017
Posts: 9
Own Kudos:
Given Kudos: 69
GMAT 1: 750 Q50 V41
GMAT 1: 750 Q50 V41
Posts: 9
Kudos: 6
Kudos
Add Kudos
Bookmarks
Bookmark this Post
pradeepmaria
mohshu
Bunuel
If p and q are integers, can (q − 1) always be expressed as an integer multiple of p?

(1) p > q
(2) q > 1

stat2: clearly not suff no info on p

stat1: p > q,, so obvious p >q-1

but what if q is 1,,then q-1 is 0 and it can expressed as integer multiple

both combined,,suff

ans C

Isnt the answer B in that case
q - 1 is not 0 and cannot always be expressed as a multiple of p - Suff.

q can be 5 and p can be 4 --> yes
q can be 2 and p can be 6 --> no
q can be 5 and p can be 3 --> no
avatar
BRATATI_GOSWAMI
Joined: 16 Apr 2017
Last visit: 05 Jul 2019
Posts: 1
Given Kudos: 38
Posts: 1
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If p and q are integers, can (q − 1) always be expressed as an integer multiple of p?

(1) p > q
(2) q > 1

Answer is C

Statement 1(p>q)
Case-1 - Let p=5 and q=-4, then (q-1=-5 is (-1) times p or 5)
Case-2 - Let p=7 and q =5, then (q-1=4 cannot be expressed as a multiple of p or 7)
Hence, Statement 1 is not sufficient.

Statement 2
Case-1 - Let p=7 and q=8, then (q-1=7 is (1) times p or 7)
Case-2 - Let p=7 and q =9, then (q-1=8 cannot be expressed as a multiple of p or 7)
Hence, Statement 2 is not sufficient.

Both Statements together
Here q is positive and >1 & p is also positive and greater than 2 (since both p & q are intergers)
Thus, p is always greater than q-1, since p & q are positive and p>q.
A small number can never be expressed as an integer multiple of a large number.
Hence, both statements together are sufficient.
User avatar
Ramyanag
Joined: 09 Dec 2014
Last visit: 30 Nov 2017
Posts: 34
Own Kudos:
Given Kudos: 25
Posts: 34
Kudos: 37
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If p and q are integers, can (q − 1) always be expressed as an integer multiple of p?

(1) p > q
(2) q > 1

We have to find whether it is possible to express (q-1) as an integer multiple of p ==> (q-1) = p * k (k is some integer multiple)

Statement 1 says p>q.
Let q= 1 and p= 4
1-1 = 0 ==> 4 * 0, for k=0 --> possible
Let q=2 and p=4
2-1 = 1 But 1 cannot be expressed as a product of 4 * k, for some integer k. --> not possible
Insufficient

Statement 2 says q>1
Nothing has been given about the value of p
Let q=2 and p=1
2-1= 1 ==> can be expressed as 1*1, for k=1 --> possible
Let q=2 and p=3
2-1=1 ==> cannot be expressed as a product of 3 * k, for some integer k --> not possible
Insufficient

On combining both statements we have.
p>q and q>1 ==> 1<q<p
As p>q ==> p>q-1
So q-1 cannot be expressed as p*k, for some integer k
Thus, we get a definite NO after combining both the statements.
Answer: C
avatar
pclawong
Joined: 07 Jun 2017
Last visit: 04 Feb 2018
Posts: 80
Own Kudos:
Given Kudos: 454
Posts: 80
Kudos: 20
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If p and q are integers, can (q − 1) always be expressed as an integer multiple of p?

(1) p > q
(2) q > 1

My answer was D
Because the question is asking "Always"
I can be wrong
User avatar
Ramyanag
Joined: 09 Dec 2014
Last visit: 30 Nov 2017
Posts: 34
Own Kudos:
Given Kudos: 25
Posts: 34
Kudos: 37
Kudos
Add Kudos
Bookmarks
Bookmark this Post
pclawong
Bunuel
If p and q are integers, can (q − 1) always be expressed as an integer multiple of p?

(1) p > q
(2) q > 1

My answer was D
Because the question is asking "Always"
I can be wrong

In order to say a statement is sufficient to answer a given question in the Yes/No type of DS question, that statement has to give you a definite YES or a definite NO. Yes, the statement is sufficient if it gives you a definite NO. But a statement is not sufficient if it gives you YES sometimes (to some values) and NO to some values. In this question, as you have also mentioned "always", each statement is giving YES and NO if you consider them individually. That is not "always". So D cannot be answer to this question as per my knowledge. If you solved in some other way and got definite YES or NO to each statement when considering individually, please share. May be I have committed some mistake while solving. :) After all, we learn more as we discuss. :-D
Moderator:
Math Expert
97847 posts