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19 Apr 2012, 03:20
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If p, q, and r are integers, is p+q+r> 0 ??
(1) p + r = q
(2) r^2 < -q
(1) p + r = q
(2) r^2 < -q
The first one is insufficient : 3 + 2 = 5 > 0 YES or 0+0=0 NO
The second one we do not know about p
Combined: from 2 q is negative (this is the meaning), so 1 is also as consequence = to a negative value .......... negative + negative < 0 always. answer is NO Suff.
here is the tricky thing: if i look at the problem as if I were during the exam and under time pressure I could say: p + r = q so we have 2q > 0 .....NO sufficient and the answer would be A not C.
BUT if I use the two statement combined with the substitution method I have
q is postive ( we know from second statement that q per se is negative but time minus we have q: positive in the end) so p + r = q --------> r = q - p
So we have p + q + q - p > 0 -------- > 2q >0 Suff, answer would be C, again.
Please clarify this weird situation. Thanks
The second one we do not know about p
Combined: from 2 q is negative (this is the meaning), so 1 is also as consequence = to a negative value .......... negative + negative < 0 always. answer is NO Suff.
here is the tricky thing: if i look at the problem as if I were during the exam and under time pressure I could say: p + r = q so we have 2q > 0 .....NO sufficient and the answer would be A not C.
BUT if I use the two statement combined with the substitution method I have
q is postive ( we know from second statement that q per se is negative but time minus we have q: positive in the end) so p + r = q --------> r = q - p
So we have p + q + q - p > 0 -------- > 2q >0 Suff, answer would be C, again.
Please clarify this weird situation. Thanks
19 Apr 2012, 03:42
Kudos
Bookmarks
carcass
If p, q, and r are integers, is p+q+r> 0 ??
(1) p + r = q
(2) r^2 < -q
The first one is insufficient : 3 + 2 = 5 > 0 YES or 0+0=0 NO
The second one we do not know about p
Combined: from 2 q is negative (this is the meaning), so 1 is also as consequence = to a negative value .......... negative + negative < 0 always. answer is NO Suff.
here is the tricky thing: if i look at the problem as if I were during the exam and under time pressure I could say: p + r = q so we have 2q > 0 .....NO sufficient and the answer would be A not C.
BUT if I use the two statement combined with the substitution method I have
q is postive ( we know from second statement that q per se is negative but time minus we have q: positive in the end) so p + r = q --------> r = q - p
So we have p + q + q - p > 0 -------- > 2q >0 Suff, answer would be C, again.
Please clarify this weird situation. Thanks
(1) p + r = q
(2) r^2 < -q
The first one is insufficient : 3 + 2 = 5 > 0 YES or 0+0=0 NO
The second one we do not know about p
Combined: from 2 q is negative (this is the meaning), so 1 is also as consequence = to a negative value .......... negative + negative < 0 always. answer is NO Suff.
here is the tricky thing: if i look at the problem as if I were during the exam and under time pressure I could say: p + r = q so we have 2q > 0 .....NO sufficient and the answer would be A not C.
BUT if I use the two statement combined with the substitution method I have
q is postive ( we know from second statement that q per se is negative but time minus we have q: positive in the end) so p + r = q --------> r = q - p
So we have p + q + q - p > 0 -------- > 2q >0 Suff, answer would be C, again.
Please clarify this weird situation. Thanks
If p, q, and r are integers, is p+q+r> 0 ?
(1) p + r = q --> original question becomes is \(q+q>0\)? --> is \(2q>0\)? --> is \(q>0\)? We don't know that, hence this statement is not sufficient.
(2) r^2 < -q --> \(q<0\) (because if q is positive (or zero) then we would have that \(r^2<negative\) (or \(r^2<0\)), which is not possible since square of a number is always non-negative). Not sufficient.
(1)+(2) From (1) the question became: "is \(q>0\)?" while (2) say that \(q<0\), hence the answer to the question is NO. Sufficient.
Answer: C.
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