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24 Mar 2011, 00:50
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If set s={7,y,12,8,,x,9} is x+y less than 18?
1.range of set s is less than 9
2.average of x and y is less than average of set s.
1.range of set s is less than 9
2.average of x and y is less than average of set s.
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24 Mar 2011, 02:19
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If range is less than 9, then the difference between the largest and teh smallest members of the set should be ,9
The difference of all the given numbers < 9
So even if we were to assume that the difference between x and y is less than 18
then let us try to find values of x and y
So x = 7 + 10 = 17
y can be the same as well = 7 + 10 = 17
So x + y can be > 18,
Again, x+y can be any other numbers as 1 and 2, and the range is still < 9.
so (1) is not sufficient.
From (2)
(x+y)/2 < (7 + y + 12 + 8 + x + 9)/6
=> 6(x+y) < 2(x+y + 36)
=> 4(x+y) < 2*36
=> (x+y) < 18
So Answer - B
The difference of all the given numbers < 9
So even if we were to assume that the difference between x and y is less than 18
then let us try to find values of x and y
So x = 7 + 10 = 17
y can be the same as well = 7 + 10 = 17
So x + y can be > 18,
Again, x+y can be any other numbers as 1 and 2, and the range is still < 9.
so (1) is not sufficient.
From (2)
(x+y)/2 < (7 + y + 12 + 8 + x + 9)/6
=> 6(x+y) < 2(x+y + 36)
=> 4(x+y) < 2*36
=> (x+y) < 18
So Answer - B
25 Mar 2011, 06:22
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AnkitK
If set s={7,y,12,8,,x,9} is x+y less than 18?
1.range of set s is less than 9
2.average of x and y is less than average of set s.
(1) x= 5, y= 11 range (12-5) is less than 9 and x+y <18 1.range of set s is less than 9
2.average of x and y is less than average of set s.
but x= 5, y= 13 here range is less than 8 but x+y=18 so INSUFFICIENT.
(2) (X+Y)/2<(7+y+12+8+x+9)/6
X+Y<18 SUFF.
ANS B
