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If set S consists of all positive integers that are multiples of both

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If set S consists of all positive integers that are multiples of both  [#permalink]

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New post 28 Jan 2019, 02:49
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

50% (01:37) correct 50% (02:27) wrong based on 35 sessions

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Concentration: Accounting, Finance
GPA: 3.68
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Re: If set S consists of all positive integers that are multiples of both  [#permalink]

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New post 28 Jan 2019, 03:38
1
Bunuel wrote:
If set S consists of all positive integers that are multiples of both 2 and 7, how many numbers in set S are between 140 and 240, inclusive?


A. 6
B. 7
C. 8
D. 9
E. 10



7*2 =14.

S consists of the integers that are multiple of 14.

140 to 240

140 = 14*10

238 = 14*17

Total number of multiples = 17 -10 +1 = 8.

C is the correct answer.
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If set S consists of all positive integers that are multiples of both  [#permalink]

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New post 28 Jan 2019, 03:49
1
Bunuel wrote:
If set S consists of all positive integers that are multiples of both 2 and 7, how many numbers in set S are between 140 and 240, inclusive?

A. 6
B. 7
C. 8
D. 9
E. 10


IMO C

Multiples of both 7 and 2, multiples of 14, will be an AP of those terms

First Term = 140, Last Term = 238

n = number of term

Last term = First term + (n-1) common difference
238 = 140 + (n-1) 14
98 /14 = n-1
7 + 1 = n

n = 8
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If set S consists of all positive integers that are multiples of both  [#permalink]

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New post 28 Jan 2019, 05:47
Bunuel wrote:
If set S consists of all positive integers that are multiples of both 2 and 7, how many numbers in set S are between 140 and 240, inclusive?


A. 6
B. 7
C. 8
D. 9
E. 10


lcm would be 14
so
140/14 = 10
240/14 = ~17
total no 17-10+1 = 8
IMO C
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If set S consists of all positive integers that are multiples of both   [#permalink] 28 Jan 2019, 05:47
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