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Re: If the digit n is the thousandths digit in the decimal d = 0.75n9, wha [#permalink]

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22 Jul 2016, 13:25

AbdurRakib wrote:

If the digit n is the thousandths digit in the decimal d = 0.75n9, what is the value of d when rounded to the nearest percentage point?

(1) When d is rounded to the nearest thousandth, its value is 0.755.

(2) 0 < n < 5

Given d = 0.75n9.

Stat 1: d is rounded to the nearest thousandth, its value is 0.755 that means n value has to be less than 5 ( n can be 4) , then from d = 0.75n9 , 9 which is greater than 5 is added to preceding number i.e 4 only then we can get 0.755.... Sufficient.

Stat 2: 0 < n < 5. When n is this range, then 9 can be added to any of n i.e. n can be 1,2,3 or 4 and based on that we get different results ( d = 0.752,0.753,0.754,0.755 ) .. Insufficient...

IMO option A is correct answer...but OA is D...

Bunuel...can you give your solution on this please or I am missing anything...

If the digit n is the thousandths digit in the decimal d = 0.75n9, wha [#permalink]

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22 Jul 2016, 17:24

msk0657 wrote:

AbdurRakib wrote:

If the digit n is the thousandths digit in the decimal d = 0.75n9, what is the value of d when rounded to the nearest percentage point?

(1) When d is rounded to the nearest thousandth, its value is 0.755.

(2) 0 < n < 5

Given d = 0.75n9.

Stat 1: d is rounded to the nearest thousandth, its value is 0.755 that means n value has to be less than 5 ( n can be 4) , then from d = 0.75n9 , 9 which is greater than 5 is added to preceding number i.e 4 only then we can get 0.755.... Sufficient.

Stat 2: 0 < n < 5. When n is this range, then 9 can be added to any of n i.e. n can be 1,2,3 or 4 and based on that we get different results ( d = 0.752,0.753,0.754,0.755 ) .. Insufficient...

IMO option A is correct answer...but OA is D...

Bunuel...can you give your solution on this please or I am missing anything...

Re: If the digit n is the thousandths digit in the decimal d = 0.75n9, wha [#permalink]

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22 Jul 2016, 23:24

rohit8865 wrote:

msk0657 wrote:

AbdurRakib wrote:

If the digit n is the thousandths digit in the decimal d = 0.75n9, what is the value of d when rounded to the nearest percentage point?

(1) When d is rounded to the nearest thousandth, its value is 0.755.

(2) 0 < n < 5

Given d = 0.75n9.

Stat 1: d is rounded to the nearest thousandth, its value is 0.755 that means n value has to be less than 5 ( n can be 4) , then from d = 0.75n9 , 9 which is greater than 5 is added to preceding number i.e 4 only then we can get 0.755.... Sufficient.

Stat 2: 0 < n < 5. When n is this range, then 9 can be added to any of n i.e. n can be 1,2,3 or 4 and based on that we get different results ( d = 0.752,0.753,0.754,0.755 ) .. Insufficient...

IMO option A is correct answer...but OA is D...

Bunuel...can you give your solution on this please or I am missing anything...

Re: If the digit n is the thousandths digit in the decimal d = 0.75n9, wha [#permalink]

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15 Feb 2017, 21:06

I feel frustrated about this - I have completed Kaplan Premier, Kaplan 800 and took GMAT twice (620 which is below my target), but I can't even understand what this question requires, what does rounding to nearest percentage point mean? I know it is Data sufficiency and we're not supposed to find answer - but would an answer look like? What is this magic number? 0.76? 76%, 75.5%, 75.49? 75.4% (this one silly, ok)?

If the digit n is the thousandths digit in the decimal d = 0.75n9, what is the value of d when rounded to the nearest percentage point?

(1) When d is rounded to the nearest thousandth, its value is 0.755.

(2) 0 < n < 5

I receive a PM asking me to comment on this question.

I have to admit I don't know what "the nearest percentage point" means. I've never seen that term used in an official GMAT math question. Based on the official answer, I'm assuming that it might be the same as rounding to the nearest hundredth.

Re: If the digit n is the thousandths digit in the decimal d = 0.75n9, wha [#permalink]

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16 Feb 2017, 23:45

GMATPrepNow wrote:

AbdurRakib wrote:

If the digit n is the thousandths digit in the decimal d = 0.75n9, what is the value of d when rounded to the nearest percentage point?

(1) When d is rounded to the nearest thousandth, its value is 0.755.

(2) 0 < n < 5

I receive a PM asking me to comment on this question.

I have to admit I don't know what "the nearest percentage point" means. I've never seen that term used in an official GMAT math question. Based on the official answer, I'm assuming that it might be the same as rounding to the nearest hundredth.

Cheers, Brent

Hi, Brent! Thanks for a response, but I still struggle with it. Rounding to the nearest hundredth is getting either 0.76 or 0.75 depending on whether the thousands is more or less than 5. (1) plain simple, if it is 0.755 when rounded to the thousands, then it is 0.76 when rounded to hundreds. but (2), if n is below 5, it can be not necessarily 4 (we know it is 4 because we're given (1), but if we ignore (1), it can be 1, 2, 3 or 4), let's assume it is 3. Then the answer can be 0.75, because 0.7539 does not get rounded to 0.76, but to 0.76? This way I find that answer to question should be A, not D. It seems to be a very easy question but it seems like it is an inaccurate one.

Re: If the digit n is the thousandths digit in the decimal d = 0.75n9, wha [#permalink]

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10 Nov 2017, 08:03

Hi ,

I think, the answer is D.

Let's understand the rules here. I am pasting the rules defined from Bunuel. Rounding is simplifying a number to a certain place value. To round the decimal drop the extra decimal places, and if the first dropped digit is 5 or greater, round up the last digit that you keep. If the first dropped digit is 4 or smaller, round down (keep the same) the last digit that you keep.

Example: 5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5. 5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5. 5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.

So, 1.425 rounded to the nearest hundredth = 1.43, since the dropped 5 is equal to 5.

With the above knowledge and understanding here is how we can solve.

"rounded to the nearest percentage point" -> means rounded to the nearest hundredth point. Statement 1 : When d is rounded to the nearest thousandth, its value is 0.755.

It means the d = 0.7549 and rounded to nearest thousandth equals to 0.755 >from the above rules rounded to nearest hundredth equals to 0.75 There is only one d value and is sufficient

Statement 2 : 0 < n < 5

Here n= 1,2,3,4

and d = 0.75n9 for all n= 1,2,3,4 we get 0.75 as the d value if round to the nearest hundredth, which is sufficient.

So d = 75 % can be obtained from both statements alone. Therefore, the answer is D.

After going through the above rules, I corrected my earlier understanding. I was thinking earlier, 5.3485 rounded to the nearest tenth = 5.4, since 5.3485 -> 5.349 ->5.35 ->5.4. Looks like this is wrong.