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31 Oct 2012, 22:42
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (02:11) correct
22%
(02:10)
wrong
based on 92
sessions
History
Date
Time
Result
Not Attempted Yet
If the number of fatalities from road accidents declined from 9,680 in 1988 to 9,600 in 1989 and then declined a further 20% from 1989 to 1990, what was the approximate percentage decline in the number of fatalities from 1988 to 1990?
(A) 12
(B) 16
(C) 21
(D) 37
(E) 43
(A) 12
(B) 16
(C) 21
(D) 37
(E) 43
31 Oct 2012, 23:59
Kudos
Bookmarks
actleader
.8*9600 = 7680
Percentage decline = \(\frac{9680-7680}{9680}*100\) = \(\frac{2000}{9680}*100\)
We can see that this is slightly higher than \(\frac{2000}{10000}*100\) ie. slightly higher than 20%
So, answer is C
Kudos Please... If my post helped
01 Nov 2012, 06:04
Kudos
Bookmarks
actleader
Actually we don't need calculate much to answer the question.
We have decline from 9,680 to 9,600 (by 80 points) and then by 20%. Now, since 80 is less than 1% of 9,680, thus the overall decline would be slightly more than 20%. Only answer choice C fits.
Answer: C.
P.S. General formula for percent increase or decrease, or percent change:
\(Percent=\frac{Change}{Original}*100\)
