pushpitkc
chetan2u
If there are four positive integers a, b, c and d in the ratio 1:2:3:4 and their sum is a perfect square, what cannot be the value of any of the four number?
(A) 10
(B) 30
(C) 90
(D) 100
(E) 1000
New question
The 4 positive numbers are in the ratio 1:2:3:4, the sum of which is 10x.
In order to eliminate answer options, let the first number(x) be one of the answer options.
The sum of the four positive integers will eliminate Option A as the sum is 100 which is \(10^2\),
Option C as the sum is 900 which is \(30^2\), and Option E as the sum if 10000 which is \(100^2\).
To eliminate one answer option between Option B and Option D,
we can assume the number 30(Option C) as the third of the four numbers(of form 3x)
Now, the sum of the 4 numbers will be 10x = 100(which is \(10^2\)) as x = 10.
Therefore,
Option D(100) is the only option that remains by elimination and is the correct answer!
pushpitkc please reveal a flaw in my reasoning below
i found two correct answers to this question !
friends would you please share your sharp math knowledge
.....
(A) 10 ( 10+20+30+40 = 100 (perfetct square)
(B) 30 ( 30+60+90+120 = 300 )
(its not a perfetct square )(C) 90 ( 90+180+270+360 (perfetct square)
(D) 100 (100+200+300+400 = 1000
(its not a perfetct square)(E) 1000 (1000+2000+3000+4000) = 10,000 (perfetct square)