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11 Jun 2010, 09:32
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A
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If x ≠ 0, what is the value of \(\sqrt{\frac{x^u}{x^v}}\) ?
(1) u = v
(2) x is a perfect square
(1) u = v
(2) x is a perfect square
11 Jun 2010, 10:46
Kudos
Bookmarks
If x ≠ 0, what is the value of \(\sqrt{\frac{x^u}{x^v}}\) ?
\(\sqrt{\frac{x^u}{x^v}}=?\)
(1) u=v --> \(\sqrt{\frac{x^u}{x^v}}=\sqrt{\frac{x^u}{x^u}}=\sqrt{1}=1\). Sufficient.
(2) x is a perfect square --> Clearly not sufficient.
Answer: A.
\(\sqrt{\frac{x^u}{x^v}}=?\)
(1) u=v --> \(\sqrt{\frac{x^u}{x^v}}=\sqrt{\frac{x^u}{x^u}}=\sqrt{1}=1\). Sufficient.
(2) x is a perfect square --> Clearly not sufficient.
Answer: A.
11 Jun 2010, 21:41
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Bunuel
hardnstrong
If x ≠ 0, what is the value of sq. root (x^u/x^v) ?
(1) u = v
(2) x is a perfect square.
OA will be posted later
(1) u = v
(2) x is a perfect square.
OA will be posted later
\(\sqrt{\frac{x^u}{x^v}}=?\)
(1) \(u=v\) --> \(\sqrt{\frac{x^u}{x^v}}=\sqrt{\frac{x^u}{x^u}}=\sqrt{1}=1\). Sufficient.
(2) x is a perfect square --> Clearly not sufficient.
Answer: A.
my question is sq. root of 1 can be +1 or -1 (like sq, root of 4 can be +2 or -2)
How can it be only 1?
please explain
OA is A
