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# If x 2, then (7x^2 + 28x + 28)/(x + 2)^2 =

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Re: If x 2, then (7x^2 + 28x + 28)/(x + 2)^2 = [#permalink]
Top Contributor
Bunuel wrote:
If x ≠ –2, then $$\frac{7x^2 + 28x + 28}{(x + 2)^2} =$$

(A) 7
(B) 8
(C) 9
(D) 10
(E) 11

Another approach:

Plug in a nice value for x and evaluate the expression.
A super nice x-value is x = 0

We get: $$\frac{7(0^2) + 28(0) + 28}{(0 + 2)^2} = \frac{28}{2^2}$$

$$= \frac{28}{4}$$

$$= 7$$

still A
Re: If x 2, then (7x^2 + 28x + 28)/(x + 2)^2 = [#permalink]
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