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If x ≠ –2, then \(\frac{7x^2 + 28x + 28}{(x + 2)^2} =\)
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
Updated on: 01 Jun 2020, 09:33
Originally posted by BrentGMATPrepNow on 01 Jun 2017, 12:45.
Last edited by BrentGMATPrepNow on 01 Jun 2020, 09:33, edited 1 time in total.
Last edited by BrentGMATPrepNow on 01 Jun 2020, 09:33, edited 1 time in total.
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Bunuel
If x ≠ –2, then \(\frac{7x^2 + 28x + 28}{(x + 2)^2} =\)
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
\(\frac{7x^2 + 28x + 28}{(x + 2)^2} = \frac{7(x^2 + 4x + 4)}{(x + 2)^2}\)
\(= \frac{7(x + 2)^2}{(x + 2)^2}\)
\(= 7\)
Answer: A
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01 Jun 2017, 12:54
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Bunuel
If x ≠ –2, then \(\frac{7x^2 + 28x + 28}{(x + 2)^2} =\)
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
\(\frac{7x^2 + 28x + 28}{(x + 2)^2} =\)\(\frac{7(x^2 + 4x + 4)}{(x^2 + 4x + 4)} =\)7
Answer: A
