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If x = 2t and y = t/3, what is the value of x^2 – y^2?
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25 Oct 2015, 08:50
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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2?
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25 Oct 2015, 09:27
Bunuel wrote: If x = 2t and y = t/3, what is the value of x^2 – y^2?
(1) t^2 – 3 = 6 (2) t^3 = −27
Kudos for a correct solution. x=2t, y=t/3, x^2 – y^2 = ? Per statement 1, t^2=9 > t= 3 or 3, after substituting both these values, you will get x^2 – y^2 = 35. Sufficient. Per statement 2, t^3=27 > t=3, 1 value and hence you will get a unique value of x^2 – y^2. Sufficient D is the correct choice.




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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2?
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26 Oct 2015, 04:26
If x = 2t and y = t/3, what is the value of x^2 – y^2? (1) t^2 – 3 = 6 (2) t^3 = −27 Sol. x^2 = 4t^2 and y^2 = t^2/9 1) t^2 = 9 so 4t^2  t^2/9 so 361 = 35 2) t^3 = −27 so t = 3 and t^2=9 so 4t^2  t^2/9 so 361 = 35 D Both Sufficient
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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2?
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26 Oct 2015, 04:36
+1 for D X^2 = 4t^2 Y^2 = t^2/9
Case 1: t^2  3 = 6; t^2 = 9, Substitue for t^2. Sufficient.
Case :2
t^3 = 27 t = 3 t^2 = 9; Substitue for t^2. Sufficient.



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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2?
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26 Oct 2015, 06:20
Bunuel wrote: If x = 2t and y = t/3, what is the value of x^2 – y^2?
(1) t^2 – 3 = 6 (2) t^3 = −27
Kudos for a correct solution. Given : x = 2t and y = t/3Question : x^2 – y^2=(x+y)*(xy) = ?Statement 1: t^2 – 3 = 6i.e. t^2 = 9 i.e. t = +3 i.e. y = +1 respectively for respective values of t= +3 i.e. x = +6 respectively for respective values of t= +3 i.e. x^2 – y^2 = ( +6)^2  ( +1)^2 = 361 = 35 SUFFICIENT Statement 2: t^3 = −27i.e. i.e. t = 3 i.e. y =1 respectively for respective values of t= +3 i.e. x =6 respectively for respective values of t= +3 i.e. x^2 – y^2 = (6)^2  (1)^2 = 361 = 35 SUFFICIENT Answer: Option D
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If x = 2t and y = t/3, what is the value of x^2 – y^2?
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07 Jan 2016, 22:07
need to find:
(2t1/3t)*(2t+1/3t)=(35/9)*t^2
St1. t^2=9, SUFF
St2. t=3, SUFF
D



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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2?
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29 Mar 2016, 07:56
Engr2012 wrote: Bunuel wrote: If x = 2t and y = t/3, what is the value of x^2 – y^2?
(1) t^2 – 3 = 6 (2) t^3 = −27
Kudos for a correct solution. x=2t, y=t/3, x^2 – y^2 = ? Per statement 1, t^2=9 > t= 3 or 3, after substituting both these values, you will get x^2 – y^2 = 35. Sufficient. Per statement 2, t^3=27 > t=3, 1 value and hence you will get a unique value of x^2 – y^2. Sufficient D is the correct choice. Can someone explain how we solve t^3 = 27? Do we multiply the statement by 1 such that we get: t^3 = 27 => t=+3 and 3? Please clarify?



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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2?
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03 Jul 2016, 11:19
startee wrote: Engr2012 wrote: Bunuel wrote: If x = 2t and y = t/3, what is the value of x^2 – y^2?
(1) t^2 – 3 = 6 (2) t^3 = −27
Kudos for a correct solution. x=2t, y=t/3, x^2 – y^2 = ? Per statement 1, t^2=9 > t= 3 or 3, after substituting both these values, you will get x^2 – y^2 = 35. Sufficient. Per statement 2, t^3=27 > t=3, 1 value and hence you will get a unique value of x^2 – y^2. Sufficient D is the correct choice. Can someone explain how we solve t^3 = 27? Do we multiply the statement by 1 such that we get: t^3 = 27 => t=+3 and 3? Please clarify? If t^odd equals to negative value k. then the number 't' has to be a negative number. \(3^3\) \(=\) \(3*3*3 = 27\) t=3(positive number.) raised to a positive number 3. \(3^3\) \(=\) \(3*3*3\) \(=\) \(27\). t=3(negative number) raised to a positive number 3. \(3^4\) \(=\) \(3*3*3*3\) \(=\)\(81\) t = 3(negative number ) raised to a positive number 4.



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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2?
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26 Jul 2017, 03:49
BunuelI went a little too far while solving this question. I got: (7t/3) (5t/3) From statement 1: t^2= 9 So t can be positive 3 or negative 3. When I plugged in the value the answer was 35 in both the cases.. My query is when we get the same answer, do we have to worry about the two values of t because we usually take one? Or we have to just consider unique value of x^2y^2? Also when its given that t^3= 27 We have to just take the negative because (negative)^odd = negative and we have to take both positive and negative values into consideration when its (value)^even....
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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2?
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25 Sep 2017, 17:42
If the question prompt wanted (x^3  y^3) or (x  y) rather than (X^2  y^2)
then statement 1 would not be sufficient, correct?



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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2?
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25 Sep 2017, 21:10



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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2?
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14 Dec 2017, 16:36
Hi All, Certain DS questions are really just a 'test' of your 'thoroughness', so it's important to do all of the necessary work (on the pad; NOT 'in your head') to prove what the correct answer is. Without having that 'proof', you might inadvertently choose the wrong answer (and miss out on some easy points on Test Day). We're told that X = 2T and Y = T/3. We're asked for the value of X^2  Y^2 1) T^2  3 = 6. With the equation in Fact 1, we can determine that T has 2 values... T^2  3 = 6 T^2 = 9 T = +3 or 3 Many Test Takers would assume that these two values would lead to two different answers to the question (and assume that Fact 1 was insufficient).... but where is your PROOF that it's insufficient...? IF.... T = 3, X=6, Y=1, then the answer to the question is 6^2  1^2 = 35 IF.... T = 3, X= 6, Y= 1, then the answer to the question is (6)^2  (1)^2 = 35 It turns out that both values of T lead to the SAME answer  and the answer to the question is ALWAYS 35. Fact 1 is SUFFICIENT 2) t^3 = 27 The equation in Fact 2 has just one solution: 3. With the work that we did in Fact 1, we know that there is only one answer to the question (35). Fact 2 is SUFFICIENT Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: If x = 2t and y = t/3, what is the value of x^2 – y^2? &nbs
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