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chetan2u
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no so much calculation required; it's simple but tricky question

(31-x)/x =>

for all x > 1 and even : (31-x) = odd so (31-x)/x [odd/even] can not be integer.
for all x > 1 and odd : (31-x) = even so (31-x)/x[even/odd] can not be integer.
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Sidhrt
no so much calculation required; it's simple but tricky question

(31-x)/x =>

for all x > 1 and even : (31-x) = odd so (31-x)/x [odd/even] can not be integer.
for all x > 1 and odd : (31-x) = even so (31-x)/x[even/odd] can not be integer.

Well I don't think calculation is at all required in this question even if we use any other method. the answer is visually and logically quite evident.
Nonetheless you have brought in an excellent approach.
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Sidhrt
no so much calculation required; it's simple but tricky question

(31-x)/x =>

for all x > 1 and even : (31-x) = odd so (31-x)/x [odd/even] can not be integer.
for all x > 1 and odd : (31-x) = even so (31-x)/x[even/odd] can not be integer.

Did you mean that even/odd can not be an integer? I know the numbers for this question will be such that it will never be an integer, but it's not true in every case.
6/3, 28/7, etc are even/odd and they are integers.
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chetan2u
If x is an integer and \(x\neq{31}\), is \(\frac{31-x}{x}\) an integer?

(1) x > 1.
(2) x is an even number.


self made -

Given: x-> z and x not equal to 31, where we know z represents integer
To find: whether 31/x - 1 -> z or rephrasing the questions as Is x a factor of 31 OR Is x =1 , as it is given that x not equal to 31

(1)x>1, every time we will get a definite answer as NO. Sufiicient

(2) again we will get a definite answer. Sufficient.

D is correct.
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