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# If x is not equal to 0 or -1, what is the value of |x-2|?

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If x is not equal to 0 or -1, what is the value of |x-2|?  [#permalink]

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Updated on: 07 Aug 2018, 06:10
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If x is not equal to 0 or -1, what is the value of |x-2|?

(1) $$\frac{(|x+1|)}{(-|x|x^3)}>0$$

(2) $$x^4 = 16$$

This is Question 1 for

Provide your solution below. Kudos for participation. Happy Solving!

Best Regards
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Originally posted by EgmatQuantExpert on 19 May 2015, 06:37.
Last edited by EgmatQuantExpert on 07 Aug 2018, 06:10, edited 4 times in total.
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Re: If x is not equal to 0 or -1, what is the value of |x-2|?  [#permalink]

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19 May 2015, 09:29
7
EgmatQuantExpert wrote:
If x is not equal to 0 or -1, what is the value of |x-2|?

(1) $$\frac{(|x+1|)}{(-|x|x^3)}>0$$

(2) $$x^4 = 16$$

This is Question 1 for

Provide your solution below. Kudos for participation. The Official Answer and Explanation will be posted on 20th May.

Till then, Happy Solving!

Best Regards
The e-GMAT Team

hi,
(1) $$\frac{(|x+1|)}{(-|x|x^3)}>0$$...
we know that for fraction to be greater than 0 both deno and numerator should be of same sign....
numeratos has to be +ive as it is mod.. so -|x|x^3 should be positive so x is a negative integer.. no other info ... insuff

(2) $$x^4 = 16$$
x can be 2 or -2... insuff

combined we get x as -2 .. suff ans C
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Re: If x is not equal to 0 or -1, what is the value of |x-2|?  [#permalink]

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19 May 2015, 09:19
2
EgmatQuantExpert wrote:
If x is not equal to 0 or -1, what is the value of |x-2|?

(1) $$\frac{(|x+1|)}{(-|x|x^3)}>0$$

(2) $$x^4 = 16$$

This is Question 1 for

Provide your solution below. Kudos for participation. The Official Answer and Explanation will be posted on 20th May.

Till then, Happy Solving!

Best Regards
The e-GMAT Team

Statement 1
Does't give you a final value of |x-2|. I tried to rearange the inequality but you can not multiply by $$-|x|x^3$$ because the term can be positive or negative (you don't know). Therefore the whole Statement 1 just tells you that some Division with X is > 0 and is therefore insufficient because it doesn't provide a VALUE for |x-2|.

Statement 2
x can be 2 or -2. Which is insufficient.

If you combine Statement 1 and 2 you know that in order to be true, Statement 1 needs a positive denominator which is just possible if X equals -2 (x^3 would then be -8 and the denominator would be -8*-2 = 16.

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Re: If x is not equal to 0 or -1, what is the value of |x-2|?  [#permalink]

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19 May 2015, 09:23
2
Statement 1 says x is negative.
Statement 2 gives 2 and -2 as values.
Combining the two we get x as -2

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Re: If x is not equal to 0 or -1, what is the value of |x-2|?  [#permalink]

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20 May 2015, 02:21
1
Stmt 1
fraction is > 0 then Numerator & Denominator need to be same sign.

Numerator |x-2| > 0

Denominator $$-|x|x^3 > 0$$ for this ( $$x^3 < 0$$) , implies x < 0 insufficient.

Stmt 2
x can be 2 or -2. insufficient.

combine 1 and 2 we get the answer, from 1 we know x < 0, and from 2 we know (x = 2 or -2)

Ans : C
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Re: If x is not equal to 0 or -1, what is the value of |x-2|?  [#permalink]

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22 May 2015, 02:58
5
1
EgmatQuantExpert wrote:
If x is not equal to 0 or -1, what is the value of |x-2|?

(1) $$\frac{(|x+1|)}{(-|x|x^3)}>0$$

(2) $$x^4 = 16$$

This is Question 1 for

Official Explanation

In order to find the value of |x-2|, we first need to know the value of x. From question statement, we know that x is not equal to 0 or -1. Let's see if St. 1 and/or 2 can get us a unique value of x.

Analyzing St. 1 Independently

$$\frac{(|x+1|)}{(-|x|x^3 )}>0$$

Multiplying both sides by a positive number doesn’t impact the sign of inequality. So, multiplying both sides by $$\frac{(|x|)}{(|x+1|)}$$, we get:

$$\frac{(-1)}{x^3} >0$$

(Note that we could multiply both sides by this number because we were told that x ≠ -1. Therefore, x + 1 ≠ 0 (division by 0 is not defined))

Now, multiplying both sides by -1 will reverse the sign of inequality. We get:

$$\frac{1}{x^3}<0$$

$$x^3$$ will have the same +/- sign as x

This means, $$1/x$$ is negative.

This means, x is negative.

This information is not sufficient to find the value of x.

Analyzing St. 2 independently
$$x^4 = 16$$

That is, $$x^4 - 2^4 = 0$$
$$(x^2 + 2^2)(x+2)(x-2) = 0$$

This gives us, x = 2 or -2

Since we don’t get a unique value of x, not sufficient.

Combining St. 1 and St. 2

From St. 1, x is negative
From St. 2, x = 2 or -2

Combining both, x = -2

Sufficient.
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Re: If x is not equal to 0 or -1, what is the value of |x-2|?  [#permalink]

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11 Jul 2016, 08:05
from the 1 statement we come to know that x is negative as we have denominator as negative.So the expression to be grater than 0 x^3 should be negative.then only it will br=e greater than zero.We do not get any definite value except x is negative.So NS

From2 statement we get that x could be 2 or -2 and both give different answers when put inside the expression.So NS

Combined we get x is negative which is only -2.And we get definite value.So answer is C.

Let me know if i am wrong.
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Re: If x is not equal to 0 or -1, what is the value of |x-2|?  [#permalink]

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17 Aug 2017, 18:28
I know this is unnecessary, but can anyone confirm that the below is correct if it was necessary to do so. Trying to make sure I understand the 3 step approach to absolute modulus.

For statement 1:

Since l x+1 l is always positive, then l x+ 1 l >0

critical point is -1,

a) so if x>-1, then x+1 is positive, so x+1>0, and x>-1,
b) if x<-1, then X+1 is negative, so -(x+1)>0, and x<-1,

so x>-1 or x<-1 right?

Denominator needs to have the same sign as the numerator, so x must be negative for denominator to be positive. so x>-1, but doesn't solve what lx-2l is.

2) x^4=16, x= 2 or -2, insuff.

c: x>-1, so x=2. Suff.

Did I handle the splitting up the modulus correctly in statement 1? Thank you! Kudos to whoever answers.
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Re: If x is not equal to 0 or -1, what is the value of |x-2|?  [#permalink]

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26 Feb 2018, 04:25
1
EgmatQuantExpert wrote:
If x is not equal to 0 or -1, what is the value of |x-2|?

(1) $$\frac{(|x+1|)}{(-|x|x^3)}>0$$

(2) $$x^4 = 16$$

X is NOT equal to -1 or 0.

|x-2| = ???

Strategically I will start with statement 2 to have sense of numbers.

Statement 2

$$x^4 = 16$$

x =2.....|2-2|= 0
or
x =-2...|-2-2|= -4

Hence it gives Two different values

Insufficient

Statement 1

From what we have let's test the answers we got:

Let x =2.........$$\frac{(|x+1|)}{(-|x|x^3)}>0$$..When x is positive, then this will make Statement 1 invalid........Discard any positive number.

Let x =-2.........$$\frac{(|x+1|)}{(-|x|x^3)}>0$$ ..Any negative number will make make Statement 1 valid...But No certain value.

Insufficient

Combine 1 & 2

From 1: We know that we need a negative number to make make it valid

From 2: We got -2

Hence we reach certain value

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Re: If x is not equal to 0 or -1, what is the value of |x-2|?  [#permalink]

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12 Jul 2019, 12:31
If x is not equal to 0 or -1, what is the value of |x-2|?

(2) $$x^4 = 16$$
Go to statement 2 first since it's easier and can provide hints.
x = 2, -2
So |x-2| = 0 or 4, Not sufficient.

(1) $$\frac{(|x+1|)}{(-|x|x^3)}>0$$
1. multiply by -1
|x+1|/|x|*x^3 < 0
2. Draw number line or test values algebraically, taking into account constraints in prompt (x≠0, -1)
Test x=1 ... 2/1*1 < 0, NO
Test x=-1/2 ... (1/2) / -(1/8) = -8 < 0, YES
Test x=-2 ... 1 / -(1/4) = -4 < 0, YES
So we have several possible solutions for x, not sufficient.

(3) Combining the two we can see that x=-2 is a valid option and x=2 is not, so |x-2| = 4, sufficient.
Re: If x is not equal to 0 or -1, what is the value of |x-2|?   [#permalink] 12 Jul 2019, 12:31
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