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22 Apr 2016, 04:32
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
65% (01:36) correct
35%
(01:16)
wrong
based on 143
sessions
History
Date
Time
Result
Not Attempted Yet
22 Apr 2016, 12:02
Kudos
Bookmarks
xy > 0 --> x and y have the same signs
Is xyz < 0?
St1: xz > 0 --> x and z have the same signs
Suppose x = +ve --> y = +ve and z = +ve --> Is xyz < 0? No
Suppose x = -ve --> y = -ve and z = -ve --> Is xyz < 0? Yes
Not Sufficient
St2: yz > 0 --> y and z have the same signs
Suppose y = +ve --> x = +ve and z = +ve --> Is xyz < 0? No
Suppose y = -ve --> x = -ve and z = -ve --> Is xyz < 0? Yes
Not Sufficient
Combining St1 and St2: xy > 0; xz > 0; yz > 0
x = +ve --> y = +ve and z = +ve
x = -ve --> y = -ve and z = -ve
Still not sufficient
Answer: E
Is xyz < 0?
St1: xz > 0 --> x and z have the same signs
Suppose x = +ve --> y = +ve and z = +ve --> Is xyz < 0? No
Suppose x = -ve --> y = -ve and z = -ve --> Is xyz < 0? Yes
Not Sufficient
St2: yz > 0 --> y and z have the same signs
Suppose y = +ve --> x = +ve and z = +ve --> Is xyz < 0? No
Suppose y = -ve --> x = -ve and z = -ve --> Is xyz < 0? Yes
Not Sufficient
Combining St1 and St2: xy > 0; xz > 0; yz > 0
x = +ve --> y = +ve and z = +ve
x = -ve --> y = -ve and z = -ve
Still not sufficient
Answer: E
30 Aug 2018, 06:24
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niks18 VeritasKarishma chetan2u pushpitkc
Is it appropriate to combine two statements
as:
xy \(z^2\) > 0
I incorrectly chose (C) here
Quote:
If xy > 0, is xyz < 0?
(1) xz > 0
(2) yz > 0
(1) xz > 0
(2) yz > 0
Is it appropriate to combine two statements
as:
xy \(z^2\) > 0
I incorrectly chose (C) here
