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saurabhsavant
rohit8865
Bunuel
If z is a positive number, is r^2 + z > z^2 + r ?

(1) r is a negative number.
(2) z is less than 1.


is (r^2-z^2)>r-z
(r-z)(r+z)>(r-z)

(1) no info of z
(2) no info of r
both statements are insuff

combining (r-z)(r+z-1)>0
As 0<z<1
if IrI<IzI then r-z<0 && ((r+z-1)<0
if IrI>IzI then r-z<0 && ((r+z-1)<0
if IrI=IzI then r-z<0 && ((r+z-1)<0

Hence suff


Ans C


Do U have an alternate approach? I didnt get ur solution..thanx

If z is a positive number, is r^2 + z > z^2 + r ?

Is r^2 + z > z^2 + r ?
Is r^2 - r > z^2 - z?

(1) r is a negative number --> r^2 - r = positive - (negative) = positive + positive = positive. So we know that the LHS is positive. We don't know about the RHS. Not sufficient.

(2) z is less than 1 --> --> since given in the stem that z is positive, then 0 < z < 1. Notice that in this range z^2 < z (for example, (1/2)^2 < 1/4). Therefore, z^2 - z < 0. We don't know about r^2 - r. Not sufficient.

(1)+(2) From above (r^2 - r) = positive > (z^2 - z) = negative. Sufficient.

Answer: C.

Hope it's clear.
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