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16 Nov 2015, 03:09
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In a survey of parents, exactly 3/4 of the mothers and 9/10 of the fathers held full-time jobs. If 40 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs?
A. 27%
B. 21%
C. 19%
D. 18%
E. 16%
A. 27%
B. 21%
C. 19%
D. 18%
E. 16%
16 Nov 2015, 03:24
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Let the total number of parents = 100
Number of women = 40
Number of men = 60
Number of mothers who held full time jobs = 3/4*40 = 30
Number of fathers who held full time jobs = 9/10*60 = 54
Total number of parents who held full time jobs = 84
Total number of parents who did not hold jobs = 100 - 84 = 16
Alternatively ,
Percentage of women = 40%
Percentage of women who did not hold full time jobs = (1-3/4)*100 % = 25% of all mothers did not have full time jobs
25% of 40 % --> 10 % of the total parents
Percentage of men = 60%
Percentage of men who held full time jobs = (1-9/10)*100% = 10% of all fathers did not have full time jobs
10 % of 60% --> 6 % of the total parents
Therefore , percentage of parents who did not hold full time jobs = 10+6=16%
Answer E - 16%
Number of women = 40
Number of men = 60
Number of mothers who held full time jobs = 3/4*40 = 30
Number of fathers who held full time jobs = 9/10*60 = 54
Total number of parents who held full time jobs = 84
Total number of parents who did not hold jobs = 100 - 84 = 16
Alternatively ,
Percentage of women = 40%
Percentage of women who did not hold full time jobs = (1-3/4)*100 % = 25% of all mothers did not have full time jobs
25% of 40 % --> 10 % of the total parents
Percentage of men = 60%
Percentage of men who held full time jobs = (1-9/10)*100% = 10% of all fathers did not have full time jobs
10 % of 60% --> 6 % of the total parents
Therefore , percentage of parents who did not hold full time jobs = 10+6=16%
Answer E - 16%
17 Nov 2015, 00:04
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Since this is a Percentage Problem, we can assume the total to be 100
Constructing a Table:
**Job|NoJob|Total
F | | 40
M | | 60
\(\frac{9}{10}\)of Men and \(\frac{3}{4}\) of women hold job => \(\frac{9}{10} * 60 = 54\) Men and \(\frac{3}{4} *40 =30\) Women hold jobs
**Job|NoJob|Total
F | 30 | | 40
M | 54 | | 60
Now, just Fill in the blanks
**Job|NoJob|Total
F |30| 10| 40
M |54| 06| 60
Therefore, total No. of Parents who do not have a job is \(10+6 = 16 => \frac{16}{100}=>16%\)
Answer is E
Constructing a Table:
**Job|NoJob|Total
F | | 40
M | | 60
\(\frac{9}{10}\)of Men and \(\frac{3}{4}\) of women hold job => \(\frac{9}{10} * 60 = 54\) Men and \(\frac{3}{4} *40 =30\) Women hold jobs
**Job|NoJob|Total
F | 30 | | 40
M | 54 | | 60
Now, just Fill in the blanks
**Job|NoJob|Total
F |30| 10| 40
M |54| 06| 60
Therefore, total No. of Parents who do not have a job is \(10+6 = 16 => \frac{16}{100}=>16%\)
Answer is E
