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In an account, m dollars decreases by 20% each year for the next

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In an account, m dollars decreases by 20% each year for the next two years. In another account, n dollars increases by 20% each year for the next two years. If the sum of the two amount at the end of two years is 100 dollars, what is the value of 4m+9n?​

a. 6.25​

b. 62.5​

c. 625​

d. 6250​

e. Cannot be determined​

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New post 22 Feb 2020, 21:34
kapil1 wrote:
In an account, m dollars decreases by 20% each year for the next two years. In another account, n dollars increases by 20% each year for the next two years. If the sum of the two amount at the end of two years is 100 dollars, what is the value of 4m+9n?​

a. 6.25​

b. 62.5​

c. 625​

d. 6250​

e. Cannot be determined​



m dollars decreases by 20% each year for the next two years ---- =>\( m*\frac{80}{100}*\frac{80}{100}=\frac{64m}{100}\).
n dollars increases by 20% each year for the next two years---- =>\( n*\frac{120}{100}*\frac{120}{100}=\frac{144m}{100}\).

If the sum of the two amount at the end of two years is 100 dollars-----=> \(\frac{64m}{100}+\frac{144n}{100}=100.....64m+144n=10000...16*4m+16*9n=16*625...4m+9n=625\)

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In an account, m dollars decreases by 20% each year for the next   [#permalink] 22 Feb 2020, 21:34
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