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23 Dec 2014, 09:52
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Tough and Tricky questions: Geometry.
In the diagram above, BD = 8, AB = 6, and ED = 5. What is the length of AE? (Note: Figure not drawn to scale.)
A. 3
B. 4
C. 5
D. 7
E. 10
Kudos for a correct solution.
Attachment:
rectangle_triangle.gif [ 2.54 KiB | Viewed 9307 times ]
beattheheat
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23 Dec 2014, 10:23
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Given: BD = 8, AB = 6, and ED = 5
Using Pythagoras theorem ==> AD = 10
AE = AD - ED = 5 , Answer C
Using Pythagoras theorem ==> AD = 10
AE = AD - ED = 5 , Answer C
23 Dec 2014, 21:41
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Bunuel
Tough and Tricky questions: Geometry.
In the diagram above, BD = 8, AB = 6, and ED = 5. What is the length of AE? (Note: Figure not drawn to scale.)
A. 3
B. 4
C. 5
D. 7
E. 10
Kudos for a correct solution.
Attachment:
rectangle_triangle.gif
AD^2 = AB^2 + BD^2 = 100 => AD = 10
AE = AD-ED = 5
ANS C
