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Re: In the figure, what is the area of triangle BCD given that the area of
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10 May 2018, 05:42
1
Solution
Given: • Area of triangle ADE = 16 • Area of triangle CDE = 12
To find: • What is the area of triangle BCD
Approach and Working: • As the triangles ACD and BCD share the same base DC, and their height is also same, they have equal area • Therefore, the area of triangle BCD = area of triangle ACD = area of triangle ADE + area of triangle CDE = 16 + 12 = 28
I have general question about irregular quadratic like the above, the sum of interior angles is 360 but does this mean the sum of opposite angles MUST equal to 180? Citing the graph above, does A+C =180 or B+D=180?
I have general question about irregular quadratic like the above, the sum of interior angles is 360 but does this mean the sum of opposite angles MUST equal to 180? Citing the graph above, does A+C =180 or B+D=180?
Thanks in advance
I believe the rule you're referring to involves a very special kind of quadrilateral, one that is inscribed in a circle (aka a cyclic quadrilateral) In that very special case, the opposite angles add to 180. More here: https://en.wikipedia.org/wiki/Cyclic_quadrilateral
Cyclic quadrilaterals are not tested on the GMAT, so you won't encounter a question in which the correct answer depends solely on this rule.
Re: In the figure, what is the area of triangle BCD given that the area of
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22 Oct 2018, 05:42
AB and DC are parallel as both make 90 deg on lie AD for triangle ADC and BCD the base is same and the height is also same. hence the area is also same we just need to find the area of ADC 16+12 = 28 (D)
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