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In the multiplication table above, each letter represents an integer.

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In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 24 Jun 2017, 04:01
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In the multiplication table above, each letter represents an integer. What is the value of c ?

(1) c=f

(2) h≠0

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Re: In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 17 Nov 2017, 12:33
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AbdurRakib wrote:
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In the multiplication table above, each letter represents an integer. What is the value of c ?

(1) c=f

(2) h≠0


We need to determine the value of c. Following our table, we have:

a x c = f

b x c = h

and

c^2 = j

Statement One Alone:

c = f

Since c = f, we have:

a x c = c

ac - c = 0

c(a - 1) = 0

c = 0 or a = 1

We see that either c = 0 or a = 1 (if c ≠ 0). Since we don’t know whether c is 0, we cannot determine the value of c. Statement one alone is not sufficient to answer the question.

Statement Two Alone:

h ≠ 0

Since h is not zero, neither b nor c is zero. However, we still can’t determine the value of c. Statement two alone is not sufficient to answer the question.

Statements One and Two Together:

Using statement two, we know that c ≠ 0, and thus from statement one, a = 1. However, c can be any nonzero number, so we still cannot determine a value for c.

Answer: E
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Re: In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 24 Jun 2017, 12:02
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(1) c=f

This will not give us a value (a number) for c ===> NOT SUFFICIENT

(2) h≠0

This will still not help us to get the value of c ===> NOT SUFFICIENT

Lets combine (1) & (2) - we will still not be able to determine the value of c

Hence, Answer is E
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Re: In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 25 Jun 2017, 13:02
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1) c=f
a)either a = 1 and c is any integer
b) c and f are both zeros .

We are not able to figure out the exact value of c .

2) h≠0
this shows that c,b≠0 . c could be any positive integer .

Taking together 1 and 2
this negates the case a . c can still be any integer except 0 .

Answer is E
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Re: In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 03 Jul 2017, 04:23
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We can see that a*c = f and b*c = h

Statement 1. c=f, This means a*c = c.
So either a=1, and then c could take any value
OR c=0, then a could take any value. We cant say anything surely about c.

Statement 2. h ≠ 0. So b*c ≠ 0
This means neither of b or c can be 0, but we cant say anything surely about c.

Combining the two statements: a*c = c, where c ≠ 0
This means definitely a = 1, but c could be any integer except 0. Insufficient.

Hence E answer
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Re: In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 24 Mar 2018, 06:20
The official explanation to this question is the following: But I still don't get it :-/


Arithmetic Properties of numbers

Given that c = f, the examples below, in which a = b = 1, show that the value of c could be 1 and the value of c could be 2; NOT sufficient.



Given that h ≠ 0, the examples in (1) show that the value of c could be 1 and the value of c could be 2; NOT sufficient.
Taking (1) and (2) together is of no more help than either (1) or (2) taken separately because the same examples used to show that (1) is not sufficient also show that (2) is not sufficient.

Both statements together are still not sufficient.
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Re: In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 26 Jul 2018, 04:13
I see a problem in this question. In the multiplication table it is stated that:
a*a= d hence "a" cannot equal 1! other wise a*a would = a. so based on my observation I chose (A). because if a doesn't equal 1 then c=0.

for whom got an explanation please answer
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Re: In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 18 Aug 2018, 01:20
there're 8 unknowns and 7 equations:
a^2=d
ab=e
af=c
b^2=g
bc=h
c^2=j
c=f
hence we cannot resolve c in this case.
does my logic make sense?
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Re: In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 12 Sep 2018, 09:09
Hi, when the question says "each letter represents an integer" is it implied that each letter represents a different integer? Could c and b be the same integer for instance? It it doesn't specify "unique integer" then how can I assume it means that?
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Re: In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 12 Sep 2018, 21:56
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gmat800live wrote:
Hi, when the question says "each letter represents an integer" is it implied that each letter represents a different integer? Could c and b be the same integer for instance? It it doesn't specify "unique integer" then how can I assume it means that?


Unless it is explicitly stated otherwise, different variables CAN represent the same number.
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Re: In the multiplication table above, each letter represents an integer.  [#permalink]

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New post 21 Sep 2018, 20:49
gmat800live wrote:
Hi, when the question says "each letter represents an integer" is it implied that each letter represents a different integer? Could c and b be the same integer for instance? It it doesn't specify "unique integer" then how can I assume it means that?


Gmat wording is too convoluted I think one has to get used to it.
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Re: In the multiplication table above, each letter represents an integer. &nbs [#permalink] 21 Sep 2018, 20:49
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