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# In the xy-plane, a quadrilateral has vertices at (-9,-2), (-1,-2) ,(-1

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Math Expert
Joined: 02 Sep 2009
Posts: 51185
In the xy-plane, a quadrilateral has vertices at (-9,-2), (-1,-2) ,(-1  [#permalink]

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25 Nov 2018, 23:44
00:00

Difficulty:

15% (low)

Question Stats:

88% (01:18) correct 12% (01:01) wrong based on 34 sessions

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In the xy-plane, a quadrilateral has vertices at (-9,-2), (-1,-2) ,(-1,-4) , and (-9,-4). What is the perimeter of the quadrilateral?

A. 4
B. 10
C. 20
D. 24
E. 32

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Re: In the xy-plane, a quadrilateral has vertices at (-9,-2), (-1,-2) ,(-1  [#permalink]

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25 Nov 2018, 23:53
Applying the distance between the points formula.

$$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$$

The distance between the points (-9,-2) & (-1,-2) is $$\sqrt{(-1+9)^2+(-2+2)^2}$$ = 8.

Similarly, for other points, we get the distance as 2,8 and 2.

Hence the perimeter is 8+2+8+2 = 20.

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Re: In the xy-plane, a quadrilateral has vertices at (-9,-2), (-1,-2) ,(-1 &nbs [#permalink] 25 Nov 2018, 23:53
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# In the xy-plane, a quadrilateral has vertices at (-9,-2), (-1,-2) ,(-1

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