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Math Expert
Joined: 02 Sep 2009
Posts: 59623

In the xyplane, a quadrilateral has vertices at (9,2), (1,2) ,(1
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26 Nov 2018, 00:44
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80% (01:21) correct 20% (01:33) wrong based on 74 sessions
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In the xyplane, a quadrilateral has vertices at (9,2), (1,2) ,(1,4) , and (9,4). What is the perimeter of the quadrilateral? A. 4 B. 10 C. 20 D. 24 E. 32
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Re: In the xyplane, a quadrilateral has vertices at (9,2), (1,2) ,(1
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26 Nov 2018, 00:53
Applying the distance between the points formula.
\(\sqrt{(x_2x_1)^2+(y_2y_1)^2}\)
The distance between the points (9,2) & (1,2) is \(\sqrt{(1+9)^2+(2+2)^2}\) = 8.
Similarly, for other points, we get the distance as 2,8 and 2.
Hence the perimeter is 8+2+8+2 = 20.
C is the answer.



Intern
Joined: 27 Nov 2018
Posts: 44

Re: In the xyplane, a quadrilateral has vertices at (9,2), (1,2) ,(1
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24 Nov 2019, 07:21
It can solved faster by drawing points in co ordinate plane. By drawing, we will come to know that it is a rectangle with one side length=8 units, second side length=2 units. Perimeter of rectangle= 2 x (l +b) = 2 x 10 = 20 which is answer C (Hit Kudos if my stated procedure helped you)




Re: In the xyplane, a quadrilateral has vertices at (9,2), (1,2) ,(1
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24 Nov 2019, 07:21






