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Is (a^2 + b^2)^1/2 an integer

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Is (a^2 + b^2)^1/2 an integer  [#permalink]

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New post Updated on: 05 Jul 2017, 00:14
1
2
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A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

56% (01:29) correct 44% (01:14) wrong based on 48 sessions

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Is \(\sqrt{a^2+b^2}\) an integer?

(1) \(a^2 + b^2\) is an integer.
(2) \(a^2 – 3b^2\) = 0

This is actually an edit from https://gmatclub.com/forum/if-b-is-an-i ... 10077.html. I made the mistake of forgetting about the part of the question that said b is an integer and of course answered the question wrong. I want to know the correct choice if the original question didn't mention b as an integer, just like I posted above.

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Originally posted by jedit on 04 Jul 2017, 23:40.
Last edited by Bunuel on 05 Jul 2017, 00:14, edited 1 time in total.
Added the OA.
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Re: Is (a^2 + b^2)^1/2 an integer  [#permalink]

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New post 04 Jul 2017, 23:50
1
jedit wrote:
Is \(\sqrt{a^2+b^2}\) an integer?

(1) \(a^2 + b^2\) is an integer.
(2) \(a^2 – 3b^2\) = 0

This is actually an edit from https://gmatclub.com/forum/if-b-is-an-i ... 10077.html. I made the mistake of forgetting about the part of the question that said b is an integer and of course answered the question wrong. I want to know the correct choice if the original question didn't mention b as an integer, just like I posted above.


The answer would be E.

If a = b = 0, then the asnwer is YES.
If \(a = \sqrt{6}\) and \(b = \sqrt{2}\), then the answer is NO.
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Re: Is (a^2 + b^2)^1/2 an integer  [#permalink]

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New post 05 Jul 2017, 00:00
Bunuel wrote:
jedit wrote:
Is \(\sqrt{a^2+b^2}\) an integer?

(1) \(a^2 + b^2\) is an integer.
(2) \(a^2 – 3b^2\) = 0

This is actually an edit from https://gmatclub.com/forum/if-b-is-an-i ... 10077.html. I made the mistake of forgetting about the part of the question that said b is an integer and of course answered the question wrong. I want to know the correct choice if the original question didn't mention b as an integer, just like I posted above.


The answer would be E.

If a = b = 0, then the asnwer is YES.
If \(a = \sqrt{6}\) and \(b = \sqrt{2}\), then the answer is NO.


I also thought E was the answer but did not post it as a question since I did not want to pose expert. Thank you for confirming and for adding OA, that would have been my next request. Kudos.
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Please hit Kudos if this post helped you inch closer to your GMAT goal.
Procrastination is the termite constantly trying to eat your GMAT tree from the inside.
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Re: Is (a^2 + b^2)^1/2 an integer   [#permalink] 05 Jul 2017, 00:00
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Is (a^2 + b^2)^1/2 an integer

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