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Is it true that x – z > y – z ? (1) xz > yz (2) x + z > y + z 09 Aug 2019, 02:47
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B
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25% (medium)

Question Stats:

66% (01:09) correct 34% (01:10) wrong based on 62 sessions

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Is it true that x – z > y – z ?

(1) xz > yz
(2) x + z > y + z
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B
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Is it true that x – z > y – z ? (1) xz > yz (2) x + z > y + z 09 Aug 2019, 10:23
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Original condition: x-z > y-z

adding z on both sides would give x>y so we need to find that which statement will give us.

1) not suff
2) suff

so Answer is B
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Is it true that x – z > y – z ? (1) xz > yz (2) x + z > y + z 09 Aug 2019, 10:25
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Statement 1 not sufficient

Case 1 X = 5 Y=3 Z= 1
Satisfy the eq
Case 2 X=-5 Y=-3 Z=-1
Doesn't satisfy the eq

Statement2 add 2Z both the sides

Satisfy the eq

Answer B
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Is it true that x – z > y – z ? (1) xz > yz (2) x + z > y + z 09 Aug 2019, 10:47
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Given x-z > y-z

Adding z both sides => x > y

Statement 1: xz > yz => divide by z gives us => x > y ..if z is +ve or x < y ...if z is -ve.......Hence INSUFFICIENT

Statement 2: x+z > y+z => subtract z both side => x > y....... Hence SUFFICIENT

The answer should be B
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Is it true that x – z > y – z ? (1) xz > yz (2) x + z > y + z 09 Aug 2019, 15:19
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Is it true that x-z>y-z?

1. xz>yz
When x=-2 and y=-1 and z=-3
Then xz=6 and yz=3
xz(6)>yz(3)
x-z=1 and y-z=2, hence can answer it is not true.
But when x=3, y=1 and z=2
Then xz=6 and yz=2, satisfying the statement that xz(6)>yz(2).
x-z=1 and y-z=—1 and the answer this time around is yes. Statement 1 is therefore insufficient.

2. x+z>y+z
This statement clearly says that x>y if we should subtract z from both sides. Once x>y, then x-z>y-z since x-z>y-z is same as x>y if z is added to both sides.

Statement alone is sufficient. The answer is B

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Is it true that x – z > y – z ? (1) xz > yz (2) x + z > y + z 09 Aug 2019, 16:43
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Is x-z > y-z?
--> is x > y?

1) xz > yz
--> if z is +ve and we divide both sides by z, then x > y (YES)
--> if z is -ve and we divide both sides by z, then x < y (NO)
NOT SUFFICIENT

2) x+z > y+z
--> x > y
SUFFICIENT


The answer is B

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