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09 Jan 2017, 03:19
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09 Jan 2017, 10:12
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k^2 can be prime only if k is not an integer. Ex: k = sqrt(11).
If k is an integer greater than 1, k^2 will have more than 2 factors.
St1: k is an integer. --> Sufficient. k^2 cannot be prime.
St2: k^2 – 1 < 0 --> k^2 < 1 --> Sufficient. k^2 cannot be prime.
Answer: D
If k is an integer greater than 1, k^2 will have more than 2 factors.
St1: k is an integer. --> Sufficient. k^2 cannot be prime.
St2: k^2 – 1 < 0 --> k^2 < 1 --> Sufficient. k^2 cannot be prime.
Answer: D
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10 Jan 2017, 04:34
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Bunuel
Is k^2 a prime number?
(1) k is an integer.
(2) k^2 – 1 < 0
(1) k is an integer.
(2) k^2 – 1 < 0
Statement 1: k is an integer
K= 0 ... k^2=0 Not prime
K=2 .....k^2=1 Not prime
K=2 or 3 oe any number means k^2 won't be prime.
Sufficient
k^2 – 1 < 0...... k^2 < 1....... -1<k< 1.......it means k is fraction.......K not prime
Sufficient
Answer: D
