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Updated on: 17 Nov 2017, 07:54
Originally posted by talismaaniac on 17 Nov 2017, 07:35.
Last edited by Bunuel on 17 Nov 2017, 07:54, edited 1 time in total.
Last edited by Bunuel on 17 Nov 2017, 07:54, edited 1 time in total.
Renamed the topic and edited the question.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
52% (00:41) correct
48%
(00:51)
wrong
based on 323
sessions
History
Date
Time
Result
Not Attempted Yet
17 Nov 2017, 07:54
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Is p=6?
(1) p^2 = 6p
p^2 - 6p = 0
p(p - 6) = 0
p = 0 or p = 6.
Not sufficient.
(2) p = even. Not sufficient.
(1)+(2) Both possible value of p from (1) are even, hence p still could be 0 as well as 6. Not sufficient.
Answer: E.
(1) p^2 = 6p
p^2 - 6p = 0
p(p - 6) = 0
p = 0 or p = 6.
Not sufficient.
(2) p = even. Not sufficient.
(1)+(2) Both possible value of p from (1) are even, hence p still could be 0 as well as 6. Not sufficient.
Answer: E.
General Discussion
17 Nov 2017, 08:00
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talismaaniac
1) \(p^2\) - 6p = 0
=> p(p-6) = 0
=> p = 0,6
Insufficient.
2) p = even
Insufficient.
1+2)
p = even & p = 0,6
Insufficient.
E is the answer
