Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options.
Updated on: 17 Nov 2017, 07:54
Originally posted by talismaaniac on 17 Nov 2017, 07:35.
Last edited by Bunuel on 17 Nov 2017, 07:54, edited 1 time in total.
Last edited by Bunuel on 17 Nov 2017, 07:54, edited 1 time in total.
Renamed the topic and edited the question.
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
51% (00:41) correct
49%
(00:51)
wrong
based on 286
sessions
History
Date
Time
Result
Not Attempted Yet
17 Nov 2017, 07:54
Kudos
Bookmarks
Is p=6?
(1) p^2 = 6p
p^2 - 6p = 0
p(p - 6) = 0
p = 0 or p = 6.
Not sufficient.
(2) p = even. Not sufficient.
(1)+(2) Both possible value of p from (1) are even, hence p still could be 0 as well as 6. Not sufficient.
Answer: E.
(1) p^2 = 6p
p^2 - 6p = 0
p(p - 6) = 0
p = 0 or p = 6.
Not sufficient.
(2) p = even. Not sufficient.
(1)+(2) Both possible value of p from (1) are even, hence p still could be 0 as well as 6. Not sufficient.
Answer: E.
General Discussion
17 Nov 2017, 08:00
Kudos
Bookmarks
talismaaniac
Is p=6?
(2) p^2 = 6p
(2) p = even
(2) p^2 = 6p
(2) p = even
1) \(p^2\) - 6p = 0
=> p(p-6) = 0
=> p = 0,6
Insufficient.
2) p = even
Insufficient.
1+2)
p = even & p = 0,6
Insufficient.
E is the answer
