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Is p=6? (2) p^2 = 6p (2) p = even

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talismaaniac
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Is p=6? (2) p^2 = 6p (2) p = even [#permalink] New post   Updated on: 17 Nov 2017, 07:54
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Is p=6?

(2) p^2 = 6p
(2) p = even
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E

Originally posted by talismaaniac on 17 Nov 2017, 07:35.
Last edited by Bunuel on 17 Nov 2017, 07:54, edited 1 time in total.
Renamed the topic and edited the question.
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Bunuel
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Re: Is p=6? (2) p^2 = 6p (2) p = even [#permalink] New post   17 Nov 2017, 07:54
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Is p=6?

(1) p^2 = 6p
p^2 - 6p = 0
p(p - 6) = 0
p = 0 or p = 6.
Not sufficient.

(2) p = even. Not sufficient.

(1)+(2) Both possible value of p from (1) are even, hence p still could be 0 as well as 6. Not sufficient.

Answer: E.
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Re: Is p=6? (2) p^2 = 6p (2) p = even [#permalink] New post   17 Nov 2017, 08:00
talismaaniac wrote:
Is p=6?

(2) p^2 = 6p
(2) p = even


1) \(p^2\) - 6p = 0
=> p(p-6) = 0
=> p = 0,6

Insufficient.

2) p = even

Insufficient.

1+2)

p = even & p = 0,6
Insufficient.

E is the answer
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Re: Is p=6? (2) p^2 = 6p (2) p = even [#permalink] New post   27 Oct 2018, 22:47
A p2p2 - 6p = 0
=> p(p-6) = 0
=> p = 0,6

Insufficient.

B p = even

Insufficient.

A+B

p = even & p = 0,6
Insufficient.

E is the answer
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Re: Is p=6? (2) p^2 = 6p (2) p = even [#permalink] New post   07 Jul 2020, 22:28
Is p=6?

1) p^2=6p
P^2-6p=0
p(p-6)=0
either p is zero or 6. two answer (Not sufficient- A,D)

2) P is even
it can be 0,2,4,6,8 (Not Sufficient - B)

3) Both together - Both 0 & 6 are possible, since both is even. (Not sufficient - C)

4) Answer is E
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Re: Is p=6? (2) p^2 = 6p (2) p = even [#permalink] New post   05 Jun 2022, 22:08
My 2 cents on this:

S1: P = 0 OR p = 6. Always remember, quadratic equations warrant OR and not AND. so P= 0 or P=6. Since two values, it is insufficient.
S2: Insufficient. P could be 20,30 or even 6.

S1 and S2 Together: P=0, or p =6, and p = even. Remember 0 is an even neutral integer so both statements combined don't add anything extra. Insufficient.

Hence, E.
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Re: Is p=6? (2) p^2 = 6p (2) p = even [#permalink]
05 Jun 2022, 22:08
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Bunuel
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