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Math Expert V
Joined: 02 Sep 2009
Posts: 58427
Is rst = 1 ? (1) r p t = s p t s (2) prt t = p t st  [#permalink]

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Difficulty:   25% (medium)

Question Stats: 72% (01:16) correct 28% (01:44) wrong based on 76 sessions

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Is rst = 1 ?

(1) $$r\sqrt{t} =\frac{s\sqrt{t}}{s}$$

(2) $$\frac{rt}{\sqrt{t}}=\frac{\sqrt{t}}{st}$$

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Joined: 07 Dec 2017
Posts: 1153
Re: Is rst = 1 ? (1) r p t = s p t s (2) prt t = p t st  [#permalink]

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Bunuel wrote:
Is rst = 1 ?

(1) $$r\sqrt{t} =\frac{s\sqrt{t}}{s}$$

(2) $$\frac{rt}{\sqrt{t}}=\frac{\sqrt{t}}{st}$$

As this looks to be a very technical question (with many equations), we'll just solve it.
This is a Precise approach.

(1) We can cancel out $$s$$ from the right-hand side giving $$r\sqrt{t} =\sqrt{t}$$
As we don't know if $$t = 0$$ or not, we can't cancel it out but we can rewrite as $$r\sqrt{t} -\sqrt{t}=0$$
This simplifies to $$\sqrt{t}(r-1)=0$$ meaning that $$t = 0$$ or $$r = 1$$.
Insufficient!

(2) Since both $$s$$ and $$t$$ are in the denominator, they can't be equal to 0 so we can multiply by them.
Multiplying by $$s$$ and by $$\sqrt{t}$$ gives $$rst = \frac{t}{t}=1$$
Sufficient!

(B) is our answer.
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Joined: 30 Oct 2017
Posts: 8
Re: Is rst = 1 ? (1) r p t = s p t s (2) prt t = p t st  [#permalink]

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DavidTutorexamPAL wrote:
Bunuel wrote:
Is rst = 1 ?

(1) $$r\sqrt{t} =\frac{s\sqrt{t}}{s}$$

(2) $$\frac{rt}{\sqrt{t}}=\frac{\sqrt{t}}{st}$$

As this looks to be a very technical question (with many equations), we'll just solve it.
This is a Precise approach.

(1) We can cancel out $$s$$ from the right-hand side giving $$r\sqrt{t} =\sqrt{t}$$
As we don't know if $$t = 0$$ or not, we can't cancel it out but we can rewrite as $$r\sqrt{t} -\sqrt{t}=0$$
This simplifies to $$\sqrt{t}(r-1)=0$$ meaning that $$t = 0$$ or $$r = 1$$.
Insufficient!

(2) Since both $$s$$ and $$t$$ are in the denominator, they can't be equal to 0 so we can multiply by them.
Multiplying by $$s$$ and by $$\sqrt{t}$$ gives $$rst = \frac{t}{t}=1$$
Sufficient!

(B) is our answer.

Can you please explain how you multiplied (2)? Cross multiply?

"2) Since both ss and tt are in the denominator, they can't be equal to 0 so we can multiply by them.
Multiplying by ss and by t√t gives rst=tt=1rst=tt=1
Sufficient!" I'm not seeing it, thanks.
Math Expert V
Joined: 02 Sep 2009
Posts: 58427
Re: Is rst = 1 ? (1) r p t = s p t s (2) prt t = p t st  [#permalink]

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mekoner wrote:
DavidTutorexamPAL wrote:
Bunuel wrote:
Is rst = 1 ?

(1) $$r\sqrt{t} =\frac{s\sqrt{t}}{s}$$

(2) $$\frac{rt}{\sqrt{t}}=\frac{\sqrt{t}}{st}$$

As this looks to be a very technical question (with many equations), we'll just solve it.
This is a Precise approach.

(1) We can cancel out $$s$$ from the right-hand side giving $$r\sqrt{t} =\sqrt{t}$$
As we don't know if $$t = 0$$ or not, we can't cancel it out but we can rewrite as $$r\sqrt{t} -\sqrt{t}=0$$
This simplifies to $$\sqrt{t}(r-1)=0$$ meaning that $$t = 0$$ or $$r = 1$$.
Insufficient!

(2) Since both $$s$$ and $$t$$ are in the denominator, they can't be equal to 0 so we can multiply by them.
Multiplying by $$s$$ and by $$\sqrt{t}$$ gives $$rst = \frac{t}{t}=1$$
Sufficient!

(B) is our answer.

Can you please explain how you multiplied (2)? Cross multiply?

"2) Since both ss and tt are in the denominator, they can't be equal to 0 so we can multiply by them.
Multiplying by ss and by t√t gives rst=tt=1rst=tt=1
Sufficient!" I'm not seeing it, thanks.

Yes, you can cross-multiply to get: rst^2 = t. Then reduce by t to get rst = 1.
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Posts: 512
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Schools: INSEAD Jan '19
GMAT 1: 700 Q50 V33 GPA: 3.95
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Re: Is rst = 1 ? (1) r p t = s p t s (2) prt t = p t st  [#permalink]

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Bunuel wrote:
Is rst = 1 ?

(1) $$r\sqrt{t} =\frac{s\sqrt{t}}{s}$$

(2) $$\frac{rt}{\sqrt{t}}=\frac{\sqrt{t}}{st}$$

Statement I:

$$\sqrt{t} (r-1) = 0$$ ---> $$t = 0 , r = 1$$

Statement II:

$$r\sqrt{t} - 1/s\sqrt{t} = 0$$
$$rst = 1.$$

So, B.
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If my Post helps you in Gaining Knowledge, Help me with KUDOS.. !! Re: Is rst = 1 ? (1) r p t = s p t s (2) prt t = p t st   [#permalink] 01 Feb 2018, 01:24
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