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Is |x|>|y|?

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cvargas92
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Is |x|>|y|? [#permalink] New post   Updated on: 22 Sep 2019, 23:28
00:00
A
B
C
D
E

Difficulty:

55% (hard)

Question Stats:

56% (00:46) correct 44% (01:51) wrong based on 9 sessions
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Hi,
I am reviewing the questions from the Official Practice Test 1. Can anybody help me understand question 3? (data sufficiency)

Is |x|>|y|?

(1) \(x^2>y^2\)
(2) x>y

Thank you!

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Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
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Official Answer
A

Originally posted by cvargas92 on 22 Sep 2019, 15:34.
Last edited by Bunuel on 22 Sep 2019, 23:28, edited 1 time in total.
Edited the OA.
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philipssonicare
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Re: Is |x|>|y|? [#permalink] New post   22 Sep 2019, 16:48
I'm unsure why statement 1 is insufficient
Absolute value determines how far a number is from zero on the number line. Squaring ensures both numbers are on the same side of zero (the positive side). This shouldn't be affected by 0<a<1, fractions, negatives etc
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Re: Is |x|>|y|? [#permalink] New post   22 Sep 2019, 18:13
philipssonicare wrote:
I'm unsure why statement 1 is insufficient
Absolute value determines how far a number is from zero on the number line. Squaring ensures both numbers are on the same side of zero (the positive side). This shouldn't be affected by 0<a<1, fractions, negatives etc


because x and y, depending whether they lie between (0, 1) or (1 , inf) change the answer.
The statement is not sufficient.
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Re: Is |x|>|y|? [#permalink] New post   22 Sep 2019, 18:19
cvargas92 wrote:
Hi,
I am reviewing the questions from the Official Practice Test 1. Can anybody help me understand question 3? (data sufficiency)

Is |x|>|y|?

(1) \(x^2>y^2\)
(2) x>y

Thank you!


I usually draw number line and divide it into 4 parts. (-Inf, -1][-1, 0],[0,1],[1, Inf)
Whenever you see squares, absolutes and inequalities like these, you need to make sure you don't forget testing the statements in any one of those parts.

1.
Statement 1 works for (x = 10, y = 5) and also for (x = .5, y = .10 ).
In first |x| > |y| but not so in 2nd
Hence it's NS

2.
Statement works for (x = 5, y = 2) and also for (x = -2, y = -5) .
So it's NS

If you combine them, then it can only work when
x and y are both positive and greater than 1. Then the combined statement is enough to answer the question.
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philipssonicare
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Re: Is |x|>|y|? [#permalink] New post   22 Sep 2019, 22:47
navderm wrote:
philipssonicare wrote:
I'm unsure why statement 1 is insufficient
Absolute value determines how far a number is from zero on the number line. Squaring ensures both numbers are on the same side of zero (the positive side). This shouldn't be affected by 0<a<1, fractions, negatives etc


because x and y, depending whether they lie between (0, 1) or (1 , inf) change the answer.
The statement is not sufficient.


This doesn't explain anything.
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Re: Is |x|>|y|? [#permalink] New post   22 Sep 2019, 23:27
Expert Reply
cvargas92 wrote:
Hi,
I am reviewing the questions from the Official Practice Test 1. Can anybody help me understand question 3? (data sufficiency)

Is |x|>|y|?

(1) \(x^2>y^2\)
(2) x>y

Thank you!


This question has a good long discussion here: https://gmatclub.com/forum/is-x-y-1-x-2 ... 46991.html
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Re: Is |x|>|y|? [#permalink] New post   22 Sep 2019, 23:27
Expert Reply
philipssonicare wrote:
I'm unsure why statement 1 is insufficient
Absolute value determines how far a number is from zero on the number line. Squaring ensures both numbers are on the same side of zero (the positive side). This shouldn't be affected by 0<a<1, fractions, negatives etc


You are right, (1) is sufficient. The OA is A, not C.

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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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Re: Is |x|>|y|? [#permalink]
22 Sep 2019, 23:27
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