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Kevin invested $8,000 for one year at a simple annual interest rate of
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17 Jun 2017, 09:03
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Kevin invested $8,000 for one year at a simple annual interest rate of 6 percent and invested $10,000 for one year at an annual interest rate of 8 percent compounded semiannually. What is the total amount of interest that Kevin earned on the two investments? A. $880 B. $1,088 C. $1,253 D. $1,280 E. $1,296 PS02209
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Re: Kevin invested $8,000 for one year at a simple annual interest rate of
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17 Jun 2017, 12:02
AbdurRakib wrote: Kevin invested $8,000 for one year at a simple annual interest rate of 6 percent and invested $10,000 for one year at an annual interest rate of 8 percent compounded semiannually. What is the total amount of interest that Kevin earned on the two investments?
A. $880 B. $1,088 C. $1,253 D. $1,280 E. $1,296 You can avoid calculation of compounded interest here. $8,000 for one year at a simple annual interest rate of 6 percent = 6/100*8,000 = $480. IF $10,000 were invested for one year at a simple annual interest rate of 8 percent, then it would earn 8/100*10,000 = $800. Since the interest is compounded semiannually, then it would earn interest on interest and actual interest would be higher. So, the answer should be slightly more than $480 + $800 = $1,280. Only E fits. Answer: E.
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Re: Kevin invested $8,000 for one year at a simple annual interest rate of
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17 Jun 2017, 09:10
AbdurRakib wrote: Kevin invested $8,000 for one year at a simple annual interest rate of 6 percent and invested $10,000 for one year at an annual interest rate of 8 percent compounded semiannually. What is the total amount of interest that Kevin earned on the two investments?
A. $880 B. $1,088 C. $1,253 D. $1,280 E. $1,296 Simple interest earned on $8000 with rate of interest 6% for 1 year.
\(SI = \frac{8000 * 6 * 1}{100} = $480\)
Amount earned on $10,000 with rate of interest 8% for 1 year compounded semi annually.
Amount \(= \frac{104}{100} * \frac{104}{100} * 10,000 = $10816\)
CI = Amount  Principal
CI \(= 10,816  10,000 = $816\)
Total amount of interest earned \(=480 + 816 = $1296\). Answer E..._________________ Please Press "+1 Kudos" to appreciate.




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Re: Kevin invested $8,000 for one year at a simple annual interest rate of
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17 Jun 2017, 09:22
From the first investment, she would have earned 480$ at 6% interest on a total amount of 8000$ From the second investment, the interest is calculated at half yearly basis The annual interest is 8%, so halfyearly interest is 4%
For the investment of 10000$, the interest for the first half of the year is 400$.Since this interest is compounded, the interest of the second half of the year is calculated for the principal of 10400$ Again the interest percentage is 4%, hence the interest for this half year is 4% of 10400 = 104*4 = 416$Therefore, total interest from both investments is 480 + 400 + 416 = 1296(Option E)
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Re: Kevin invested $8,000 for one year at a simple annual interest rate of
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15 Nov 2017, 15:57
AbdurRakib wrote: Kevin invested $8,000 for one year at a simple annual interest rate of 6 percent and invested $10,000 for one year at an annual interest rate of 8 percent compounded semiannually. What is the total amount of interest that Kevin earned on the two investments?
A. $880 B. $1,088 C. $1,253 D. $1,280 E. $1,296 We’ll use the simple interest formula for both parts of this question: I = P x r x t , where I = interest, P = principal, r = the annual interest rate, and t = the number of years (or part of a year) for which interest is earned. Let’s first determine what Kevin earned from the $8,000 at 6 percent simple interest for 1 year: 8000 x 0.06 x 1 = $480 Next let’s determine what Kevin earned from the $10,000 for one year at an annual interest rate of 8 percent compounded semiannually. Note that semiannual compounding means that interest is computed twice a year, so for the first half of the year, we use t = 1/2: 10,000 x 0.08 x 1/2 = 10,000 x 0.08 x 1/2 = $400 = interest for the first half of the year. Thus, the new principal is 10,000 + 400 = $10,400. This new principal earns interest for the second half of the year: 10,400 x 0.08 x 1/2 = $416 So, the total interest earned on the $10,000 was 400 + 416 = 816. From the two investments, therefore, Kevin earned 480 + 816 = $1,296 in interest. Answer: E
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Re: Kevin invested $8,000 for one year at a simple annual interest rate of
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20 Nov 2017, 16:58
Hi All, We're told that Kevin made two investments: 1) $8,000 for one year at a simple annual interest rate of 6 percent 2) $10,000 for one year at an annual interest rate of 8 percent compounded semiannually. We're asked for the total amount of interest that Kevin earned on the two investments. This question requires that we use the two interest formulas: Simple Interest = Principal x (1+rt) Compound Interest = Principal x (1+r)^t Where r and t are the interest rate/year and the amount of time (in years). The first investment = $8,000(1.06) = $8,480 > $480 in interest The second investment calculates the interest SEMIANNUALLY, so we have to double the value of t, but halve the value of r.... The second investment = $10,000(1.04)^2 While that calculation might look a bit 'complex', we don't actually have to complete it. The first interest payment would equal $400 (since that is 4% of $10,000), but the second payment would be slightly HIGHER (since we'd be taking 4% of $10,400). Thus, the TOTAL interest would equal $480 + $400 + (a little more than $400) = More than $1280. There's only one answer that matches... Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: Kevin invested $8,000 for one year at a simple annual interest rate of
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04 Jul 2018, 21:10
(\(\frac{6}{100}\))(8,000) = (6)(80) = $480
(\(\frac{4}{100}\))(10,000) = (4)(400) = $400
(In the second half of the year the principal will be $10,000 + $400 = $10,400)
(\(\frac{4}{100}\))(10,400) = (4)(104) = $416
480 + 400 + 416 = 480 + 816 = $1,296
Answer E.




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