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Director  B
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Kim and Sue each bought some roses and some daisies at the prices show  [#permalink]

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Difficulty:   75% (hard)

Question Stats: 58% (02:01) correct 42% (02:24) wrong based on 1563 sessions

### HideShow timer Statistics Kim and Sue each bought some roses and some daisies at the prices shown above.If Kim bought the same total number of roses and daisies as Sue,was the price of Kim's purchase of roses and daisies higher than the price of Sue's purchase of roses and daisies?

(1) Kim bought twice as many daisies as roses
(2) Kim bought 4 more roses than Sue bought

Attachment: 2018.OG.06.339.q.jpg [ 10.47 KiB | Viewed 18324 times ]
Math Expert V
Joined: 02 Aug 2009
Posts: 8340
Re: Kim and Sue each bought some roses and some daisies at the prices show  [#permalink]

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AbdurRakib wrote: Kim and Sue each bought some roses and some daisies at the prices shown above.If Kim bought the same total number of roses and daisies as Sue,was the price of Kim's purchase of roses and daisies higher than the price of Sue's purchase of roses and daisies?

(1) Kim bought twice as many daisies as roses
(2) Kim bought 4 more roses than Sue bought

Attachment:
2018.OG.06.339.q.jpg

hi,

two things - roses and daisies - are involved, in which roses cost more than daisies.
Now K and S purchase same number of flowers (roses and daisies).

so since the roses cost more, anyone who has purchased MORE roses as compared to the other will have spent more money..

let's see the statements..

(1) Kim bought twice as many daisies as roses
nothing about what S has bought..
If S purchased say equal number of roses and daisies, S spent more
If S purchased say THRICE as many daisies as roses, K spent more as he bought more roses as compared to K
Insuff

(2) Kim bought 4 more roses than Sue bought
This is what we were looking for.
so K bought 4 more roses, thus spent 4*(1-0.5)=$2 more suff B _________________ Target Test Prep Representative V Status: Founder & CEO Affiliations: Target Test Prep Joined: 14 Oct 2015 Posts: 9031 Location: United States (CA) Re: Kim and Sue each bought some roses and some daisies at the prices show [#permalink] ### Show Tags 2 3 AbdurRakib wrote: Kim and Sue each bought some roses and some daisies at the prices shown above.If Kim bought the same total number of roses and daisies as Sue,was the price of Kim's purchase of roses and daisies higher than the price of Sue's purchase of roses and daisies? (1) Kim bought twice as many daisies as roses (2) Kim bought 4 more roses than Sue bought Attachment: 2018.OG.06.339.q.jpg Since they bought the same total number of flowers, and roses are more expensive than daisies per flower, the person who purchased more roses spent more money than the other person. So, the question becomes this: Did Kim purchase more roses than Sue did? If yes, then Kim spent more money than Sue did. If not, then Kim spent less money than Sue did. Statement One Alone: Kim bought twice as many daisies as roses. Even though we know that Kim bought twice as many daisies as roses, we don’t know anything about the number of roses and the number of daisies Sue bought. Thus, we can’t tell who bought more roses. Statement one alone is not sufficient. Statement Two Alone: Kim bought 4 more roses than Sue bought. Since Kim bought more roses than Sue did, she also spent more money on the flowers than Sue did. Statement two alone is sufficient. Answer: B _________________ # Scott Woodbury-Stewart Founder and CEO Scott@TargetTestPrep.com See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews If you find one of my posts helpful, please take a moment to click on the "Kudos" button. ##### Most Helpful Community Reply Senior Manager  P Joined: 02 Apr 2014 Posts: 463 Location: India Schools: XLRI"20 GMAT 1: 700 Q50 V34 GPA: 3.5 Re: Kim and Sue each bought some roses and some daisies at the prices show [#permalink] ### Show Tags 22 9 Kim -> a (no of roses) + b (no of daises) Sue -> c (no of roses) + d (no of daises) given: $$a + b = c + d$$ (as kim and sue bought same total number of flowers) question: $$a + 0.5 * b > c + 0.5 * d$$ ? => $$2a + b > 2c + d$$ ? (multiplied by 2) => $$a + a + b > 2c + d$$ ? => $$a + c + d > 2c + d$$ (as $$a + b = c + d$$) => $$a > c$$ ? question is simplified: Did kim bought more number of roses than sue bought ? Statement 1: Kim bought twice as many daisies as roses => $$b = 2a$$ , but we want to find if $$a > c$$ ? no idea about sue => InSufficient Statement 2: Kim ($$a$$) bought 4 more roses than Sue ($$c$$) bought => directly answers our simplified question = Answer (B) ##### General Discussion Senior PS Moderator V Joined: 26 Feb 2016 Posts: 3296 Location: India GPA: 3.12 Re: Kim and Sue each bought some roses and some daisies at the prices show [#permalink] ### Show Tags 3 2 From the question stem we are able to get the cost/flower Rose - 1$ and Daisies - 0.5$Given the sum of roses and daisies bought by Kim and Sue are the same. (1) Kim bought twice as many daisies as rose If the number of roses bought by Kim is x, the number of daisies she bought are 2x Total number of flowers bought is 3x Since we have absolutely no idea bout which flowers Sue bought, this statement alone is not sufficient. (2) Kim bought 4 more roses than Sue bought If Sue bought x roses, Kim bought x+4 roses. If the total number of flowers they bought are y, Sue bought y-x daisies and Kim bought y-x-4 daisies Since the total flowers bought by both of them is the same, we can clearly tell that the flowers cost Kim 2$ higher overall. Sufficient (Option B)
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Joined: 24 Jan 2017
Posts: 58
Re: Kim and Sue each bought some roses and some daisies at the prices show  [#permalink]

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1
1
B.

We want to know if Kim's total purchase is greater than that of Sue's.

Given: Kim and Sue bought the same total number of flowers.
Price of roses is higher than that of daisies.

Task: In order for Kim's total purchase to be greater than Sue's, either:
a. Kim bought more roses than did Kim.
b. Kim bought fewer daisies than did Kim.

(1) Kim bought twice as many daisies as roses
We do not know about the number of roses Sue bought, thus we cannot know if Sue bought more roses than Kim or not. INSUFFICIENT
(2) Kim bought 4 more roses than Sue bought
Situation a. above. SUFFICIENT.
Manager  S
Joined: 23 May 2017
Posts: 230
Concentration: Finance, Accounting
WE: Programming (Energy and Utilities)
Re: Kim and Sue each bought some roses and some daisies at the prices show  [#permalink]

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can anyone please solve statement B
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Concentration: General Management, Entrepreneurship
Re: Kim and Sue each bought some roses and some daisies at the prices show  [#permalink]

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Leo8 wrote:
can anyone please solve statement B

The primary thing to understand here is that the person who buys more roses than the other will have a higher purchase cost. For example, say Kim has 2 extra roses, and given the fact that both of them have equal number of flower, therefore, Sue will have 2 lesser roses, (i.e.) 2 more daisies. In the end, Kim's purchase is $1 more than Sue's. Statement 1: No information is given about Sue, so INSUFFICIENT. Statement 2: Kim has 4 more roses, therefore, Sue has 4 daisies in that place and hence the net is$4 (Kim) - $2 (Roses) =$2.
Sue paid: c + $$\frac{d}{2}$$ $(c and d are number of roses and daises Sue bought respectively) a+b = c+d was the price of Kim's purchase of roses and daisies higher than the price of Sue's purchase of roses and daisies meaning did Kim pay more than Sue? so a + $$\frac{b}{2}$$ > c + $$\frac{d}{2}$$ ? or 2a + b > 2c + d? because a+b = c+d, so we can reduce both sides to get a>c? If we know the relationship between a and c, we can answer the question. Statement 1: b = 2a. No c, so INSUFF Statement2: a-c=4. SUFF Answer is B Originally posted by NamVu1990 on 25 Aug 2017, 01:39. Last edited by NamVu1990 on 05 Sep 2017, 00:08, edited 1 time in total. Intern  B Joined: 18 Nov 2017 Posts: 39 Re: Kim and Sue each bought some roses and some daisies at the prices show [#permalink] ### Show Tags hellosanthosh2k2 wrote: Kim -> a (no of roses) + b (no of daises) Sue -> c (no of roses) + d (no of daises) given: $$a + b = c + d$$ (as kim and sue bought same total number of flowers) question: $$a + 0.5 * b > c + 0.5 * d$$ ? => $$2a + b > 2c + d$$ ? (multiplied by 2) => $$a + a + b > 2c + d$$ ? => $$a + c + d > 2c + d$$ (as $$a + b = c + d$$) => $$a > c$$ ? question is simplified: Did kim bought more number of roses than sue bought ? Statement 1: Kim bought twice as many daisies as roses => $$b = 2a$$ , but we want to find if $$a > c$$ ? no idea about sue => InSufficient Statement 2: Kim ($$a$$) bought 4 more roses than Sue ($$c$$) bought => directly answers our simplified question = Answer (B) Could anyone please explain this step? Why has 0.5 been multiplied with b and d? $$a + 0.5 * b > c + 0.5 * d$$ ? Manager  S Joined: 22 Jan 2014 Posts: 168 WE: Project Management (Computer Hardware) Re: Kim and Sue each bought some roses and some daisies at the prices show [#permalink] ### Show Tags 1 101mba101 wrote: hellosanthosh2k2 wrote: Kim -> a (no of roses) + b (no of daises) Sue -> c (no of roses) + d (no of daises) given: $$a + b = c + d$$ (as kim and sue bought same total number of flowers) question: $$a + 0.5 * b > c + 0.5 * d$$ ? => $$2a + b > 2c + d$$ ? (multiplied by 2) => $$a + a + b > 2c + d$$ ? => $$a + c + d > 2c + d$$ (as $$a + b = c + d$$) => $$a > c$$ ? question is simplified: Did kim bought more number of roses than sue bought ? Statement 1: Kim bought twice as many daisies as roses => $$b = 2a$$ , but we want to find if $$a > c$$ ? no idea about sue => InSufficient Statement 2: Kim ($$a$$) bought 4 more roses than Sue ($$c$$) bought => directly answers our simplified question = Answer (B) Could anyone please explain this step? Why has 0.5 been multiplied with b and d? $$a + 0.5 * b > c + 0.5 * d$$ ? that is the price per unit of daisies. _________________ Illegitimi non carborundum. Intern  B Joined: 18 Nov 2017 Posts: 39 Re: Kim and Sue each bought some roses and some daisies at the prices show [#permalink] ### Show Tags thefibonacci wrote: 101mba101 wrote: hellosanthosh2k2 wrote: Kim -> a (no of roses) + b (no of daises) Sue -> c (no of roses) + d (no of daises) given: $$a + b = c + d$$ (as kim and sue bought same total number of flowers) question: $$a + 0.5 * b > c + 0.5 * d$$ ? => $$2a + b > 2c + d$$ ? (multiplied by 2) => $$a + a + b > 2c + d$$ ? => $$a + c + d > 2c + d$$ (as $$a + b = c + d$$) => $$a > c$$ ? question is simplified: Did kim bought more number of roses than sue bought ? Statement 1: Kim bought twice as many daisies as roses => $$b = 2a$$ , but we want to find if $$a > c$$ ? no idea about sue => InSufficient Statement 2: Kim ($$a$$) bought 4 more roses than Sue ($$c$$) bought => directly answers our simplified question = Answer (B) Could anyone please explain this step? Why has 0.5 been multiplied with b and d? $$a + 0.5 * b > c + 0.5 * d$$ ? that is the price per unit of daisies. Oh ok. Thanks! I got very confused with the question and missed out on that part. Director  P Joined: 14 Dec 2017 Posts: 505 Location: India Re: Kim and Sue each bought some roses and some daisies at the prices show [#permalink] ### Show Tags AbdurRakib wrote: Kim and Sue each bought some roses and some daisies at the prices shown above.If Kim bought the same total number of roses and daisies as Sue,was the price of Kim's purchase of roses and daisies higher than the price of Sue's purchase of roses and daisies? (1) Kim bought twice as many daisies as roses (2) Kim bought 4 more roses than Sue bought Attachment: 2018.OG.06.339.q.jpg Let the total # of roses & daises bought be 10. Let Kim buy "x" roses & hence she will buy (10 - x) daisies Let Sue buy "y" roses & hence she will buy (10 - y) daisies Purchase of Kim = x + 0.5*(10 - x) & Purchase of Sue = y + 0.5*(10 - y) Question:is x + 0.5*(10 - x) > y + 0.5*(10 - y)? Simplified to, is x > y ? Statement 1: Kim bought twice as many daisies as roses. No information about Sue's purchase. Statement 1 alone is Not Sufficient. Statement 2: Kim bought 4 more roses than Sue. x = y + 4. Hence x > y Statement 2 is Sufficient. Answer B. Thanks, GyM _________________ Manager  S Joined: 07 Feb 2017 Posts: 174 Re: Kim and Sue each bought some roses and some daisies at the prices show [#permalink] ### Show Tags sue spent R+.5D 1. Kim spent r+r=2r; count R+D=3r Total count divisible by 3 Kim spent 2/3(R+D) Is 2/3(R+D) > R+D/2? 1/6D > 1/3R? D > 2R? Example: D=2; R=1; sue spent$2; Kim spent $2 D=7; R=2; sue spent$5.5; Kim spent $6 Insufficient 2. r=R+4 d=R+D-R-4=D-4 Kim spent R+4+.5(D-4)=R+.5D+2$2 more than sue
Sufficient

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Re: Kim and Sue each bought some roses and some daisies at the prices show  [#permalink]

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AbdurRakib wrote: Kim and Sue each bought some roses and some daisies at the prices shown above.If Kim bought the same total number of roses and daisies as Sue,was the price of Kim's purchase of roses and daisies higher than the price of Sue's purchase of roses and daisies?

(1) Kim bought twice as many daisies as roses
(2) Kim bought 4 more roses than Sue bought

Attachment:
2018.OG.06.339.q.jpg

If Kim bought the same total number of roses and daisies as Sue and if Kim bought 4 more roses than Sue bought, its quite logical that option B is sufficient Intern  B
Joined: 31 Oct 2018
Posts: 7
Location: Viet Nam
Kim and Sue each bought some roses and some daisies at the prices show  [#permalink]

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this took me embarrassingly long (7 min). on my 2nd try i just plugged in numbers. could someone tell me is this thinking process correct.
From Q: Nk = Ns
From S1: Kim has 2 times daisies => e.g Kim has 12 daisies then she has 6 roses . nothing about Sue => S1 insufficient
From S2: Kim has 4 more roses than Sue => Sue has 2 roses and 12+6 - 2 = 16 daisies. => all quantities known => sufficient to say prices => S2 is sufficient
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GMAT 1: 690 Q50 V34 Re: Kim and Sue each bought some roses and some daisies at the prices show  [#permalink]

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AbdurRakib wrote: Kim and Sue each bought some roses and some daisies at the prices shown above.If Kim bought the same total number of roses and daisies as Sue,was the price of Kim's purchase of roses and daisies higher than the price of Sue's purchase of roses and daisies?

(1) Kim bought twice as many daisies as roses
(2) Kim bought 4 more roses than Sue bought

Attachment:
2018.OG.06.339.q.jpg

Given:
1. Kim and Sue each bought some roses and some daisies at the prices shown above.
2. Kim bought the same total number of roses and daisies as Sue

Asked: Was the price of Kim's purchase of roses and daisies higher than the price of Sue's purchase of roses and daisies?

(1) Kim bought twice as many daisies as roses
There are 2 possibilities
1. Sue purchased more than twice as many daisies as roses
2. Sue purchased less than twice as many daisies as roses
The answers will be different in both cases
NOT SUFFICIENT

(2) Kim bought 4 more roses than Sue bought
Since there total is same (say T)
Let roses bought by Sue be x, daisies bought by Sue = T-x; Total price = x + .5(T-x) = .5x+.5T
Then roses bought by Kim will be x+4, Daisies bought by Kim = T-x-4; Total price = x+4 + .5(T-x-4) = .5(x+4) + .5T = .5x + .5T + 2
The price of Kim's purchase of roses and daisies was higher than the price of Sue's purchase of roses and daisies
SUFFICIENT

IMO B Re: Kim and Sue each bought some roses and some daisies at the prices show   [#permalink] 18 Sep 2019, 22:09
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# Kim and Sue each bought some roses and some daisies at the prices show  