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macjas
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02 Jun 2012, 23:48
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D
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Kyle and Reed together have p baseball cards, where p is a positive integer. Reed has q less baseball cards then Kyle, where q is a positive integer less than p. Which of the following represents the number of baseball cards Kyle has?
A. (p-q)/2
B. (p+2)/q
C. p/q
D. (p+q)/2
E. 2q - p
A. (p-q)/2
B. (p+2)/q
C. p/q
D. (p+q)/2
E. 2q - p
03 Jun 2012, 03:43
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macjas
Kyle and Reed together have p baseball cards, where p is a positive integer. Reed has q less baseball cards then Kyle, where q is a positive integer less than p. Which of the following represents the number of baseball cards Kyle has?
A. (p-q)/2
B. (p+2)/q
C. p/q
D. (p+q)/2
E. 2q - p
A. (p-q)/2
B. (p+2)/q
C. p/q
D. (p+q)/2
E. 2q - p
Say Kyle has K cards and Reed has R cards.
Given:
K+R=P
K-R=Q
Sum these two equations: (K+R)+(K-R)=P+Q --> 2K=P+Q --> K=(P+Q)/2.
Answer: D.
macjas
Joined: 09 May 2012
Last visit: 30 Jul 2015
Posts: 308
Own Kudos:
Given Kudos: 100
Affiliations: UWC
Location: Canada
Schools: Rotman '15 (A) Schulich '15 (M)
GMAT 1: 620 Q42 V33
GMAT 2: 680 Q44 V38
GPA: 3.43
WE:Engineering (Media/Entertainment)
Products:
10 Jun 2012, 00:35
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What is wrong with this algebraically:
K+R = P
R+Q = K
R+Q+R = P
2R = P-Q
R = (P-Q)/2
I know this is the wrong answer, but isn't this algebraically sound? So where is the discrepancy?
K+R = P
R+Q = K
R+Q+R = P
2R = P-Q
R = (P-Q)/2
I know this is the wrong answer, but isn't this algebraically sound? So where is the discrepancy?
Gotta read the questions more carefully!! 
